   Chapter 10.5, Problem 35E

Chapter
Section
Textbook Problem

# Find an equation for the conic that satisfies the given conditions.35. Parabola, vertex (3, −1), horizontal axis, passing through (−15, 2)

To determine

To Find: The equation for the conic using the vertex (3,1) through horizontal axis and point (15,2) of the parabola.

Explanation

Given:

Vertex is (3,1) and point is (15,2) of the parabola.

The parabola is in horizontal axis.

Therefore, the standard form of parabola equation is like y2=4py .

Calculation:

Compute the value of p using the equation below.

(yk)2=4p(xh)

Substitute of the vertex (3,1) for (h,k) and point (15,2) for (x,y) .

(2(1))2=4p(153)32=4p(18)9=72pp=972p=18p=18

Compute the equation of the parabola using the below equation

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