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Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270336

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Section
BuyFindarrow_forward

Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270336
Textbook Problem

Find an equation for the conic that satisfies the given conditions.

35. Parabola, vertex (3, −1), horizontal axis, passing through (−15, 2)

To determine

To Find: The equation for the conic using the vertex (3,1) through horizontal axis and point (15,2) of the parabola.

Explanation

Given:

Vertex is at (3,1) and the point (15,2) is on the parabola.

The parabola is in horizontal axis.

Therefore, the standard form of parabola equation is like (yk)2=4p(xh).

Calculation:

It is given that the vertex is at (3,1) and the point (15,2) is on the parabola.

Substitute of the vertex (3,1) for (h,k) and point (15,2) for (x,y).

(2(1))2=4p(153)3

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Chapter 10 Solutions

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