   Chapter 10.5, Problem 36E

Chapter
Section
Textbook Problem

# Find an equation for the conic that satisfies the given conditions.36. Parabola, vertical axis, passing through (0, 4), (1, 3), and (−2, −6)

To determine

To Find: The equation for the conic using the vertical axis passing through the points (0,4) , (1,3) and (2,6) .

Explanation

Given:

The points are passing through points (0,4) , (1,3) and (2,6) .

Calculation:

The parabola is with the vertical axis. So, Standard equation of the parabola is as below,

y=ax2+bx+c

Compute the value of a and b using the given points and the equation below.

y=ax2+bx+c (1)

Substitute the point (0,4) for (x,y) in equation (1).

4=a(0)2+b(0)+cc=4

Substitute the point (1,3) for (x,y) and 4 for c in equation (1).

3=a(1)2+b(1)+4a+b=34

a+b=1 (2)

Substitute the point (2,6) for (x,y) and 4 for c in equation (1).

6=a(2)2+b(2)+44a2b=64

4a2b=10

Divide the equation by 2

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Find f'(a). f(t)=2t+1t+3

Single Variable Calculus: Early Transcendentals, Volume I

#### In Exercises 2340, find the indicated limit. 28. limt3(4t22t+1)

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### The area of the shaded region is given by:

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th

#### True or False: converges.

Study Guide for Stewart's Multivariable Calculus, 8th 