   Chapter 10.5, Problem 92E Finite Mathematics and Applied Cal...

7th Edition
Stefan Waner + 1 other
ISBN: 9781337274203

Solutions

Chapter
Section Finite Mathematics and Applied Cal...

7th Edition
Stefan Waner + 1 other
ISBN: 9781337274203
Textbook Problem

The 2014 Ebola Outbreak In the first 6 months of the 2014 Ebola outbreak, the total number of reported deaths form Ebola could be approximated by D ( t ) = 90.52 e 0.60 t        ( 0 ≤ t ≤ 6 ) , What t is time in months since April 1, 2014.68 Estimate D ( 5 )  and  d D d t | t − 5 andinterpret your answers.

To determine

To calculate: The value of function D(t)=90.52e0.60t at t=5, dDdt|t=5 and interpret answer. Where D(t) represents the number of death cases of Ebola from 1 April 2014 if function is D(t)=90.52e0.60t, where 0t6 here t is number of months.

Explanation

Given information:

The number of death cases of Ebola reported is represented by D(t)=90.52e0.60t here 0t6

Here, t represents the number of months.

Formula used:

The instantaneous rate of change represents the derivative of the function.

The balance difference quotient of a function f(x) at any point a is f(a)f(a+h)f(ah)2h

Calculation:

Consider the expression D(t)=90.52e0.60t that represents the number of death cases of Ebola.

Evaluate the value of D(5) by substituting 5 for t in expression D(t)=90.52e0.60t

D(5)=90.52e0.60(5)1818

Let h=0.001 and a=5.

Now substitute 0.001 for h and 5 for a in expression D(a)D(a+h)D(ah)2h.

Evaluate the value of dDdt|t=5,

D(5)D(5+0.001)D(50.0001)2(0.0001)D(5.0001)D(4.9999)0.0002

Evaluate the value of D(5

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