General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Chapter 10.6, Problem 10.7PP
Interpretation Introduction
Interpretation:
The complete nuclear reaction for fission of uranium-235 by neutron bombardment to give three neutrons, antimony-133, and one other isotope should be predicted.
Concept Introduction:
The reactions involving the formation of a new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.
To write a nuclear reaction the chemical equation for the reaction must be balanced, that is, the sum of
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Chapter 10 Solutions
General, Organic, and Biological Chemistry - 4th edition
Ch. 10.1 - Complete the following table for two isotopes of...Ch. 10.1 - Prob. 10.1PCh. 10.1 - Prob. 10.2PCh. 10.1 - Prob. 10.3PCh. 10.1 - Identify Q in each of the following symbols. a....Ch. 10.2 - Prob. 10.5PCh. 10.2 - Prob. 10.6PCh. 10.2 - Prob. 10.7PCh. 10.2 - Prob. 10.2PPCh. 10.2 - Prob. 10.8P
Ch. 10.2 - Prob. 10.3PPCh. 10.2 - Prob. 10.9PCh. 10.2 - Prob. 10.10PCh. 10.2 - Prob. 10.11PCh. 10.3 - Prob. 10.4PPCh. 10.3 - Prob. 10.12PCh. 10.3 - Prob. 10.13PCh. 10.3 - Prob. 10.14PCh. 10.4 - To treat a thyroid tumor, a patient must be given...Ch. 10.4 - A sample of iodine-131 (t1/2=8.0 days) has an...Ch. 10.4 - Prob. 10.15PCh. 10.5 - Prob. 10.16PCh. 10.5 - Prob. 10.17PCh. 10.5 - Prob. 10.18PCh. 10.6 - Prob. 10.7PPCh. 10.6 - Prob. 10.8PPCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Prob. 36PCh. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Prob. 43PCh. 10 - Prob. 44PCh. 10 - Prob. 45PCh. 10 - Prob. 46PCh. 10 - Prob. 47PCh. 10 - Prob. 48PCh. 10 - Prob. 49PCh. 10 - Prob. 50PCh. 10 - Prob. 51PCh. 10 - Prob. 52PCh. 10 - Prob. 53PCh. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - Prob. 56PCh. 10 - Prob. 57PCh. 10 - Prob. 58PCh. 10 - Prob. 59PCh. 10 - Prob. 60PCh. 10 - Prob. 61PCh. 10 - Prob. 62PCh. 10 - Prob. 63PCh. 10 - Prob. 64PCh. 10 - Prob. 65PCh. 10 - Prob. 66PCh. 10 - Prob. 67PCh. 10 - Prob. 68PCh. 10 - Prob. 69PCh. 10 - Prob. 70PCh. 10 - Prob. 71PCh. 10 - Prob. 72PCh. 10 - Prob. 73PCh. 10 - Prob. 74PCh. 10 - Prob. 75PCh. 10 - Prob. 76PCh. 10 - Prob. 77PCh. 10 - Prob. 78PCh. 10 - Prob. 79PCh. 10 - Prob. 80PCh. 10 - Prob. 81PCh. 10 - Prob. 82PCh. 10 - Prob. 83PCh. 10 - Prob. 84PCh. 10 - Prob. 85PCh. 10 - Prob. 86PCh. 10 - Prob. 87PCh. 10 - Prob. 88PCh. 10 - Prob. 89CPCh. 10 - Prob. 90CP
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- How did you get this? k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs 0.693 a 102.0 nanogram(ng) sample of sodium-24 was stored in a lead-lined cabinet for 2.5 days How much sodium-24 remained? The half-life os sodium -24 is 15 hours _________ ng sodium -24 remain check_circle Expert Answer thumb_up thumb_down Step 1 Radioactive decay is a first order reaction. Conversion of days into hours: 1 day2.5 days===24 hrs2.5×2460 hrs1 day=24 hrs2.5 days=2.5×24=60 hrs Calculation of k: k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs-1 Step 2 Radioactive decay is a first order reaction, therefore: [A]=[Ao] e−kt[A]=[Ao] e-kt where [A] is the final amount remained at time t, [Ao] is the initial amount. Putting values: [A]====102.0 ng×e−0.0462 hrs−1×60 hrs102.0 ng×e−2.772102.0 ng×0.062546.38 ng[A]=102.0 ng×e-0.0462 hrs-1×60 hrs=102.0 ng×e-2.772=102.0 ng×0.06254=6.38 ng Thus 6.38 ng of sodium-24 remained.arrow_forwardBRINE SOLUTION PROBLEM: In 1986 the Chernobyl nuclear power plant exploded, and scattered radioactive material over Europe. Of particular note were the two radioactive elements iodine-131 whose half-life is 8 days and cesium-137 whose half-life is 30 years. Predict how much of this material would remain over time. Express your final answer as a function of t.arrow_forwardProblem 9-6 A radioactive isotope in a 9.0-mL vial has an intensity of 300. mCi. A patient is required to take 50. mCi intravenously. How much liquid should be used for the injection?arrow_forward
- co-60 is used for radiation therapy as implants and as external source of radiation exposure. The half life of Co-60 is 5,272 years. how much of a 2.000 mg sample will remain after 21,088 years? Please show work.arrow_forwardSHOW FULL SOL The initial amount of the radioactive material B in a rock is determined to be 19.08 mg. Only 0.0038 g are left of B after 1,980 years. How much of the radioactive material B decayed? Express your final answer in four decimal places A. 3.8000 mg B. 15.2800 mg C. 0.1530 g D. 1.5280 garrow_forwardProblem 9-5 Barium-122 has a half-life of 2 minutes. Suppose you obtained a sample weighing 10.0 g and it takes 10 minutes to set up an experiment in which the barium-122 is to be used. How many grams of barium-122 will remain at the point when you begin the experiment?arrow_forward
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