   Chapter 10.6, Problem 29E

Chapter
Section
Textbook Problem

# The planet Mercury travels in an elliptical orbit with eccentricity 0.206. Its minimum distance from the sun is 4.6 × 107 km. Find its maximum distance from the sun.

To determine

To find: The maximum distance from the sun.

Explanation

Given:

• Eccentricity of the ellipse is 0.206
• Minimum distance from the sun is 4.6×107km

Calculation:

Calculate minimum distance at perihelion.

r=α(1e) (1)

Substitute 4.6×107km for r and 0.206 for e in the equation (1).

4.6×107=α(10.206)α=4.6×10710.206=4.6×1070.794

Calculate the maximum distance from the sun

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