   Chapter 10.8, Problem 1.2ACP

Chapter
Section
Textbook Problem

Based on the graph from question 1, predict the altitude where the partial pressure of oxygen is 90 mm Hg.

Interpretation Introduction

Interpretation:

The altitude has to be predicted where the partial pressure of oxygen is 90mmHg

Concept Introduction:

Pressure=ForceArea

Pressure can be expressed in different units. But it is normally reported in mmHg(millimetersofmercury)

Atmospheric pressure vs altitude:

Atmospheric pressure goes on decreases as we move to higher altitudes.

AMS (Acute Mountain Sickness) is a common problem for avid skiers which have the symptoms like headache, nausea, fatigue etc.

Explanation

As we go to higher altitudes, atmospheric pressure decreases.  This condition will lead the skiers to have symptoms like headache, nausea dizziness etc.

From the given values of altitude and pressure the relation between altitude and pressure can be understood.

 Altitude(m) Pressure(mm Hg) 0 760 3000 532 5000 380 8848 220

Using these values we can draw the graph and it is clear that there is a significant deviation from linearity at the highest altitudes.  But the relationship at lower altitude is almost linear.

The graph of altitude vs atmospheric pressure is a non-linear one and confirms the relationship between altitude and atmospheric pressure.

Figure 1

Considering the first three points in the graph we get a straight line and the x-coordinates and y-coordinates are labelled in the graph given below.

Figure 2

We can identify the altitude at 90mmHg using the straight line equation

y=mx+cwheremistheslopecis the y intercept

Slope,m=ΔyΔx=760-5320-3000=-0

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