Chapter 10.8, Problem 2.2ACP

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Use the data provided in Table 10.1 to calculate the density of dry air at 1.00 atm and 25 °C.

Interpretation Introduction

Interpretation:

The density of dry air at 1atmand25°C using the data in the table 10.1 has to be calculated.

Concept Introduction:

Density of a gas can be find out with the help of ideal gas equation which is

PV=nRT

n in the given equation can be written as mM Since amount of any substance is given by dividing mass with molar mass.

PV=mMRTmV=PMRTdensity=PMRT

Explanation

We know that densityâ€‰=â€‰PMRT

Given:

â€‚Â Pâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰â€‰â€‰â€‰â€‰1â€‰atmTâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰298K

 Constituent Molar mass Mole percent Partial pressures at STP (atm) N2 28.01 78.08 0.7808 O2 32 20.95 0.2095 Ar 39.95 0.934 0.00934 CO2 44.01 0.0393 0.000393 Â Â Â Â

Table 10.1

From this table we can calculate the molecular mass:

â€‚Â Mâ€‰=â€‰(28.01â€‰g/mol)(0.7808)â€‰+â€‰(32â€‰g/mol)(0.2095)â€‰+â€‰(39.95â€‰g/mol)(0

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