   Chapter 10.8, Problem 2.2ACP

Chapter
Section
Textbook Problem

Use the data provided in Table 10.1 to calculate the density of dry air at 1.00 atm and 25 °C.

Interpretation Introduction

Interpretation:

The density of dry air at 1atmand25°C using the data in the table 10.1 has to be calculated.

Concept Introduction:

Density of a gas can be find out with the help of ideal gas equation which is

PV=nRT

n in the given equation can be written as mM Since amount of any substance is given by dividing mass with molar mass.

PV=mMRTmV=PMRTdensity=PMRT

Explanation

We know that density=PMRT

Given:

P=1atmT=298K

 Constituent Molar mass Mole percent Partial pressures at STP (atm) N2 28.01 78.08 0.7808 O2 32 20.95 0.2095 Ar 39.95 0.934 0.00934 CO2 44.01 0.0393 0.000393

Table 10.1

From this table we can calculate the molecular mass:

M=(28.01g/mol)(0.7808)+(32g/mol)(0.2095)+(39.95g/mol)(0

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