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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

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BuyFindarrow_forward

Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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In Exercises 21 and 22, find the intersection of the graphs of the two equations by graphing.

4 x - 3 y = - 3

x + 2 y = 13

To determine

To find:

The point of intersection of the two lines 4x-3y=-3 and x+2y=13 using graph.

Explanation

The slope m and the y intercept b of a line y=mx+b are used to graph the given equations.

Rearrange 4x-3y=-3 into y=mx+b as follows,

Move 4x to the right side of the equation.

So,

-3y=-4x-3

y=-4x-3-3

y=-4x-3+-3-3

y=43x+1

The graph of y=43x+1 is a line with y-intercept b=1 and slope m=43

Rearrange x+2y=13 into y=mx+b as follows,

Move x to the right side of the equation.

So,

2y=-x+13

y=-x+132

y=-x2+132

y=-12x+132

y=-12x+132

The graph of y=-12x+132 is a line with y-intercept b=132 and slope m=-12

To draw a graph,

Substitute x=0 in the given equation 4x-3y=-3,

40-3y=-3

-3y=-3

Divide both sides by -3,

-3y-3=-3-3

y=1

Thus the first point is 0, 1

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