   Chapter 11, Problem 100AE

Chapter
Section
Textbook Problem

# If the fluid inside a tree is about 0.1 M more concentrated in solute than the groundwater that bathes the roots, how high will a column of fluid rise in the tree at 25°C? Assume that the density of the fluid is 1.0 g/cm3. (The density of mercury is 13.6 g/cm3.)

Interpretation Introduction

Interpretation: The height of a fluid’s column raised in tree has to be calculated.

Concept Interpretation:

When a semipermeable membrane, separates a solution and pure solvent. The solvent molecules are passed through the semi permeable membrane. There is gradual increase in the volume of solution with a decrease in volume of the solvent with respect to time. The flow of solvent through a semipermeable membrane into the solution is called as osmosis. By the time system reaches equilibrium, the changes in the liquid level stops. There is a higher hydrostatic pressure on the solution than compared to that of the pure solvent because there is variation in the liquid levels at this point. The excess pressure on the solution is called osmotic pressure.

The osmotic pressure of solution is calculated by using,

Π=MRT

Here,

Π=osmoticpressure(in atm)

M=molarityofsolution(inM)

R=Gasconstant

T=Temperature(inK)

Explanation

Record the given info

Densityoffluid=1.0gcm-3Temperature=25°CMolarityoffluid=0.1M

To calculate the osmotic pressure

Π=MRT

Π=0.1molL×0

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