Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 11, Problem 11.17E
Interpretation Introduction
Interpretation:
The validation of the expression
Concept introduction:
The Schrödinger equation for one-dimensional harmonic oscillator is,
Where,
•
•
•
•
• The value of constant
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Normalize the wave function ψ= A sin (nπ/a x) by finding the value of the constant A when the particle is restricted to move in one dimensional box of width ‘a’.
Chapter 11 Solutions
Physical Chemistry
Ch. 11 - Convert 3.558mdyn/A into units of N/m.Ch. 11 - Prob. 11.2ECh. 11 - Prob. 11.3ECh. 11 - Prob. 11.4ECh. 11 - Prob. 11.5ECh. 11 - Prob. 11.6ECh. 11 - Prob. 11.7ECh. 11 - Prob. 11.8ECh. 11 - Prob. 11.9ECh. 11 - Prob. 11.10E
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- For a particle in a state having the wavefunction =2asinxa in the range x=0toa, what is the probability that the particle exists in the following intervals? a x=0to0.02ab x=0.24ato0.26a c x=0.49ato0.51ad x=0.74ato0.76a e x=0.98ato1.00a Plot the probabilities versus x. What does your plot illustrate about the probability?arrow_forwardFor the same system as in Exercise E7C.3(a) (Functions of the form sin(nπx/L), where n = 1, 2, 3 …, are wavefunctions in a region of length L (between x = 0 and x = L). Show that the wavefunctions with n = 1 and 2 are orthogonal; you will find the necessary integrals in the Resource section) ,show that the wavefunctions with n = 2 and 4 are orthogonal.arrow_forwardFor a particle in a box of length L and in the state with n = 3, at what positions is the probability density a maximum? At what positions is the probability density zero?arrow_forward
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