Chapter 11, Problem 11.23UKC

(a)

Interpretation Introduction

Interpretation:

The molecular formula of anethole has to be written.

Concept Introduction:

Explanation of Solution

The given compound is anethole. The molecular formula of anethole is $C_{10}{H}_{12}O.$  The structure can be represented as follows,

    

(b)

Interpretation Introduction

Interpretation:

The functional group present in anethole has to be identified.

Explanation of Solution

The functional groups present in anethole can be represented as follows,

    

(c)

Interpretation Introduction

Interpretation:

The carbon-carbon double bond present in anethole has to be labeled as cis or tans.

Concept Introduction:

Cis isomer: When the two functional groups are present on the same side of the double bond, then the compound is said to be as cis isomer.

Trans isomer: When the two functional groups are present on the opposite side of the double bond, then the compound is said to be as trans isomer.

Explanation of Solution

The given compound is anethole.  There is only one carbon-carbon double bond present apart from the aromatic ring and the adjacent alkyl moieties are placed in the opposite side of the double hence it is trans isomer and it can be shown as follows,

(d)

Interpretation Introduction

Interpretation:

The structure of anethole can be drawn and each carbon as trigonal planar of tetrahedral has to be labeled.

Explanation of Solution

The shape of $s{p}^3,s{p}^2,\text{and}sp$ hybridized carbon atom is tetrahedral, trigonal planar, and linear respectively.  Based on hybridization present in each of the carbon atom can be labeled as tetrahedral, trigonal planar, or linear as follows,