Second-order rate constants used in modeling atmospheric chemistry are commonly reported in units of cm 3 molecule- 1 s-1. Convert the following rate constants to L mol- 1 s-1: 3.5 × 10 − 14 cm 3 molecule-1 s-1 7.1 × 10 − 18 cm 3 molecule-1 s-1 6.1 × 10 − 30 cm 3 molecule- 1 s-1

Question

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Answer 1

Textbook Question

Chapter 11, Problem 11.24PAE

Second-order rate constants used in modeling atmospheric chemistry are commonly reported in units of cm³ molecule-¹s-1. Convert the following rate constants to L mol-¹s-1:

3.5 × 10 − 14

cm³ molecule-1 s-1

7.1 × 10 − 18

cm³ molecule-1 s-1

6.1 × 10 − 30

cm³ molecule-¹s-1

Expert Solution

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

(b)

Expert Solution

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.

(c)

Expert Solution

Interpretation Introduction

To determine:

Convert 6.1×10−30

molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

6.1×10−30cm3

molecule−1s−1

=6.1×10−30cm3molecule.s=6.1× 10 −30×( 1 1000 L)( 1 6.022× 10 23 )mol.s=6.1× 10 −30×6.022× 10 231000Lmol−1s−1=3.7×10−9Lmol−1s−1.

Conclusion

Conversion factor to convert cm3

molecule−1s−1 to Lmol−1s−1 is 6.022×1020

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Answer 2

Textbook Question

Chapter 11, Problem 11.24PAE

Second-order rate constants used in modeling atmospheric chemistry are commonly reported in units of cm³ molecule-¹s-1. Convert the following rate constants to L mol-¹s-1:

3.5 × 10 − 14

cm³ molecule-1 s-1

7.1 × 10 − 18

cm³ molecule-1 s-1

6.1 × 10 − 30

cm³ molecule-¹s-1

Expert Solution

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

(b)

Expert Solution

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.

(c)

Expert Solution

Interpretation Introduction

To determine:

Convert 6.1×10−30

molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

6.1×10−30cm3

molecule−1s−1

=6.1×10−30cm3molecule.s=6.1× 10 −30×( 1 1000 L)( 1 6.022× 10 23 )mol.s=6.1× 10 −30×6.022× 10 231000Lmol−1s−1=3.7×10−9Lmol−1s−1.

Conclusion

Conversion factor to convert cm3

molecule−1s−1 to Lmol−1s−1 is 6.022×1020

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Answer 3

Textbook Question

Chapter 11, Problem 11.24PAE

Second-order rate constants used in modeling atmospheric chemistry are commonly reported in units of cm³ molecule-¹s-1. Convert the following rate constants to L mol-¹s-1:

3.5 × 10 − 14

cm³ molecule-1 s-1

7.1 × 10 − 18

cm³ molecule-1 s-1

6.1 × 10 − 30

cm³ molecule-¹s-1

Expert Solution

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

(b)

Expert Solution

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.

(c)

Expert Solution

Interpretation Introduction

To determine:

Convert 6.1×10−30

molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

6.1×10−30cm3

molecule−1s−1

=6.1×10−30cm3molecule.s=6.1× 10 −30×( 1 1000 L)( 1 6.022× 10 23 )mol.s=6.1× 10 −30×6.022× 10 231000Lmol−1s−1=3.7×10−9Lmol−1s−1.

Conclusion

Conversion factor to convert cm3

molecule−1s−1 to Lmol−1s−1 is 6.022×1020

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Answer 4

Textbook Question

Chapter 11, Problem 11.24PAE

Second-order rate constants used in modeling atmospheric chemistry are commonly reported in units of cm³ molecule-¹s-1. Convert the following rate constants to L mol-¹s-1:

3.5 × 10 − 14

cm³ molecule-1 s-1

7.1 × 10 − 18

cm³ molecule-1 s-1

6.1 × 10 − 30

cm³ molecule-¹s-1

Expert Solution

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

(b)

Expert Solution

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.

(c)

Expert Solution

Interpretation Introduction

To determine:

Convert 6.1×10−30

molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

6.1×10−30cm3

molecule−1s−1

=6.1×10−30cm3molecule.s=6.1× 10 −30×( 1 1000 L)( 1 6.022× 10 23 )mol.s=6.1× 10 −30×6.022× 10 231000Lmol−1s−1=3.7×10−9Lmol−1s−1.

Conclusion

Conversion factor to convert cm3

molecule−1s−1 to Lmol−1s−1 is 6.022×1020

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

(b)

Expert Solution

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.

(c)

Expert Solution

Interpretation Introduction

To determine:

Convert 6.1×10−30

molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

6.1×10−30cm3

molecule−1s−1

=6.1×10−30cm3molecule.s=6.1× 10 −30×( 1 1000 L)( 1 6.022× 10 23 )mol.s=6.1× 10 −30×6.022× 10 231000Lmol−1s−1=3.7×10−9Lmol−1s−1.

Conclusion

Conversion factor to convert cm3

molecule−1s−1 to Lmol−1s−1 is 6.022×1020

Answer 8

Expert Solution

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

To determine:

Convert 3.5×10−14cm3molecule−1s−1 to L mol−1s1.

Answer 13

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

3.5×10−14cm3molecule−1s−1=3.5×10−14cm3molecule.s=3.5× 10 −14×( 1 1000 L)( 1 6.022× 10 23 mol)×s=3.5× 10 −141000×6.022×1023Lmol−1s−1=3.5×6.022×10−6=2.1×107Lmol−1s−1

Answer 14

(b)

Expert Solution

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.

Answer 15

(b)

Expert Solution

Answer 16

(b)

Expert Solution

Answer 17

Expert Solution

Answer 18

Interpretation Introduction

To determine:

Find the value of 7.1×10−18cm3molecule−1s−1 to L mol−1s−1

Answer 19

Explanation of Solution

1cm3=11000L

1molecule=16.022×1023mol

7.1×10−18cm3molecule−1s−1=7.1× 10 −18cm31molecule×sputing the value you get=( 7.1× 10 −18 )×( 1 1000 L)( 1 6.022× 10 23 mol)×( 1s)=7.1× 10 −18×6.022× 10 231000 Lmol.s=4.275×103Lmol−1s−1=4.3×103Lmol−1s−1.