Concept explainers
i.
The allowable load for the pinned-pinned end condition.
i.
Answer to Problem 11.4.6P
The allowable load for the pinned-pinned condition is 677.94 kN
Explanation of Solution
Given:
E=200 GPa
L= 7.5 m
Factor of of safety = 2.5
Column type: W250×89
Concept Used:
Calculation:
Conclusion:
The allowable load for the pinned-pinned condition is 677.97 kN
ii.
The allowable load for the fixed-free end condition.
ii.
Answer to Problem 11.4.6P
The allowable load for the fixed-free end condition is 169.49 kN
Explanation of Solution
Given:
E=200 GPa
L= 7.5 m
Factor of of safety = 2.5
Column type: W250×89
Concept Used:
Calculation:
Conclusion:
The allowable load for the fixed-free end condition is 169.49 kN
iii.
The allowable load for the fixed-pinned end condition.
iii.
Answer to Problem 11.4.6P
The allowable load for the fixed-pinned end condition is 1387.58 kN
Explanation of Solution
Given:
E=200 GPa
L= 7.5 m
Factor of of safety = 2.5
Column type: W250×89
Concept Used:
Calculation:
Conclusion:
The allowable load for the fixed-pinned end condition is 1387.58 kN
iv.
The allowable load for the fixed-fixed end condition.
iv.
Answer to Problem 11.4.6P
The allowable load for the fixed-fixed end condition is 2711.90 kN
Explanation of Solution
Given:
E=200 GPa
L= 7.5 m
Factor of of safety = 2.5
Column type: W250×89
Concept Used:
Calculation:
Conclusion:
The allowable load for the fixed-fixed end condition is 2711.90 kN
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Chapter 11 Solutions
Mechanics of Materials (MindTap Course List)
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- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning