# A quantity of ice at 0.0°C was added to 33.6 g of water at 21.0°C to give water at 0.0°C. How much ice was added? The heat of fusion of water is 6.01 kJ/mol and the specific heat is 4.18 J/(g · °C).

### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343

Chapter
Section

### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343
Chapter 11, Problem 11.46QP
Textbook Problem
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## A quantity of ice at 0.0°C was added to 33.6 g of water at 21.0°C to give water at 0.0°C. How much ice was added? The heat of fusion of water is 6.01 kJ/mol and the specific heat is 4.18 J/(g · °C).

Interpretation Introduction

Interpretation:

The amount of ice added to water has to determined.

### Explanation of Solution

Given data

Amount of water = 33.6g at 21°C

Heat of fusion o0f water = 6.01kJ/mol

Specific heat of water = 4.18J/(g.°C)

To determine: heat released by cooling

Heat released by cooling =[(33.6g)(0.0°C-21.0°C(4.18J/g.°C] <

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