   Chapter 11, Problem 11P

Chapter
Section
Textbook Problem

A 5.00-g lead bullet traveling at 3.00 × 102 m/s is stopped by a large tree. If half the kinetic energy of the bullet is transformed into internal energy and remains with the bullet while the other half is transmitted to the tree, what is the increase in temperature of the bullet?

To determine
The increase in temperature of the bullet.

Explanation

Given Info: mass of the lead bullet is 5.00 g, speed of the bullet is 3.00×102m/s ,  Half the kinetic energy of the bullet is transformed into internal energy and remains with the bullet and the other half is transmitted to the tree.

Formula to calculate the kinetic energy is,

KE=12mv2

• KE is the kinetic energy of the bullet,
• m is the mass of the bullet,
• v is the speed of the bullet,

Formula to calculate the increase in internal energy of the bullet is,

Q=mcΔT

• Q is increase in internal energy of the bullet,
• c is the specific heat capacity of the lead,
• ΔT is the change in temperature,

Half of the kinetic energy used to increase the internal energy of the bullet.

Formula to calculate the increase in internal energy of the bullet is,

Q=12(KE)

Use 1/2mv2 for KE and mcΔT for Q in the above expression and rearrange it in terms of ΔT

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