   Chapter 11, Problem 18P

Chapter
Section
Textbook Problem

Lead pellets, each of mass 1.00 g, are heated to 200.°C. How many pellets must be added to 0.500 kg of water that is initially at 20.0°C to make the equilibrium temperature 25.0°C? Neglect any energy transfer to or from the container.

To determine
How many pellets must be added  to water to raise its temperature for 20.0°C to 25.0°C .

Explanation

Given Info: mass of each pellet is 1.00 g, initial temperature of the pellet is  200°C , mass of the water is 0.500 kg, initial temperature of the pellet is 20.0°C , and final equilibrium temperature is 25.0°C .

Formula to calculate Heat gained by water is,

QW=mWcW(TfTiW)

• QW is the heat gained by water,
• mW is the mass of water,
• cW is the specific heat of water,
• TiW is the initial temperature of water,
• Tf is the final temperature of water,

Formula to calculate Heat lost by pellet is,

Qpl=Nmplcpl(TfTipl)

• Qpl is the heat lost by lead pellet,
• mpl is the mass of each pellet,
• cpl is the specific heat of lead,
• Tipl is the initial temperature of pellet,
• N is the number of pellets,

Heat gained by the water is heat lost by the pellet QW=Qpl .

Equate both heat energy equations and rewrite it in terms of m.

mWcW(TfTiW)=Nmplcpl(TfTipl)N=mWcW(TfTiW)mplcpl(TfTipl)

Substitute 1

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