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PhysicsCollege Physics11th Edition

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Chapter 11, Problem 25P
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Solutions

Chapter
Section
Problem 1CQ
Problem 2CQ
Problem 3CQ
Problem 4CQ
Problem 5CQ
Problem 6CQ
Problem 7CQ
Problem 8CQ
Problem 9CQ
Problem 10CQ
Problem 11CQ
Problem 12CQ
Problem 13CQ
Problem 14CQ
Problem 15CQ
Problem 16CQ
Problem 1P
Problem 2P
Problem 3P
Problem 4P
Problem 5P
Problem 6P
Problem 7P
Problem 8P
Problem 9P
Problem 10P
Problem 11P
Problem 12P
Problem 13P
Problem 14P
Problem 15P
Problem 16P
Problem 17P
Problem 18P
Problem 19P
Problem 20P
Problem 21P
Problem 22P
Problem 23P
Problem 24P
Problem 25P
Problem 26P
Problem 27P
Problem 28P
Problem 29P
Problem 30P
Problem 31P
Problem 32P
Problem 33P
Problem 34P
Problem 35P
Problem 36P
Problem 37P
Problem 38P
Problem 39P
Problem 40P
Problem 41P
Problem 42P
Problem 43P
Problem 44P
Problem 45P
Problem 46P
Problem 47P
Problem 48P
Problem 49P
Problem 50P
Problem 51P
Problem 52P
Problem 53P
Problem 54P
Problem 55AP
Problem 56AP
Problem 57AP
Problem 58AP
Problem 59AP
Problem 60AP
Problem 61AP
Problem 62AP
Problem 63AP
Problem 64AP
Problem 65AP
Problem 66AP
Problem 67AP
Problem 68AP
Problem 69AP
Problem 70AP
Problem 71AP
Problem 72AP
Problem 73AP
Problem 74AP
Problem 75AP
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A Styrofoam cup holds 0.275 kg of water at 25.0°C. Find the final equilibrium temperature after a 0.100-kg block of copper at 90.0°C is placed in the water. Neglect any thermal energy transfer with the Styrofoam cup.

To determine
The final equilibrium temperature.

Explanation

Given Info: Mass of water is 0.275 kg, Initial temperature of water is 25.0°C , mass of copper is 0.100 kg, and initial temperature of copper is 90.0°C .

The heat lost by the copper is equal to the heat gained water.

Formula to calculate Heat gained by water is,

QW=mWcW(Tf−TiW)

  • QW is the heat gained by water,
  • mW is the mass of water,
  • cW is the specific heat of water,
  • TiW is the initial temperature of water,
  • Tf is the final temperature of water,

Formula to calculate Heat lost by copper block is,

QCu=mCucCu(Tf−TiCu)

  • QCu is the heat lost by copper block,
  • mCu is the mass of copper block,
  • cCu is the specific heat of copper block,
  • TiCu is the initial temperature of copper block,

The heat lost by the copper block is equal to the heat gained by water.

QW=−QCu

Use mAlcAl(Tf−TiAl) for QAl and mCucCu(Tf−TiCu) for QCu mWcW(Tf−TiW) to rewrite in terms of Tf .

mWcW(Tf−TiW)=−mCucCu(Tf−TiCu)mWcWTf−mWcWTiW=−mCucCuTf+m</

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Sect-11.2 P-11.1QQSect-11.4 P-11.2QQSect-11.5 P-11.3QQSect-11.5 P-11.4QQSect-11.5 P-11.5QQCh-11 P-1CQCh-11 P-2CQCh-11 P-3CQCh-11 P-4CQCh-11 P-5CQ
Ch-11 P-6CQCh-11 P-7CQCh-11 P-8CQCh-11 P-9CQCh-11 P-10CQCh-11 P-11CQCh-11 P-12CQCh-11 P-13CQCh-11 P-14CQCh-11 P-15CQCh-11 P-16CQCh-11 P-1PCh-11 P-2PCh-11 P-3PCh-11 P-4PCh-11 P-5PCh-11 P-6PCh-11 P-7PCh-11 P-8PCh-11 P-9PCh-11 P-10PCh-11 P-11PCh-11 P-12PCh-11 P-13PCh-11 P-14PCh-11 P-15PCh-11 P-16PCh-11 P-17PCh-11 P-18PCh-11 P-19PCh-11 P-20PCh-11 P-21PCh-11 P-22PCh-11 P-23PCh-11 P-24PCh-11 P-25PCh-11 P-26PCh-11 P-27PCh-11 P-28PCh-11 P-29PCh-11 P-30PCh-11 P-31PCh-11 P-32PCh-11 P-33PCh-11 P-34PCh-11 P-35PCh-11 P-36PCh-11 P-37PCh-11 P-38PCh-11 P-39PCh-11 P-40PCh-11 P-41PCh-11 P-42PCh-11 P-43PCh-11 P-44PCh-11 P-45PCh-11 P-46PCh-11 P-47PCh-11 P-48PCh-11 P-49PCh-11 P-50PCh-11 P-51PCh-11 P-52PCh-11 P-53PCh-11 P-54PCh-11 P-55APCh-11 P-56APCh-11 P-57APCh-11 P-58APCh-11 P-59APCh-11 P-60APCh-11 P-61APCh-11 P-62APCh-11 P-63APCh-11 P-64APCh-11 P-65APCh-11 P-66APCh-11 P-67APCh-11 P-68APCh-11 P-69APCh-11 P-70APCh-11 P-71APCh-11 P-72APCh-11 P-73APCh-11 P-74APCh-11 P-75AP

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