BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.1, Problem 27E

(a)

To determine

To find: the simplest value of 23(632) .

Expert Solution

Answer to Problem 27E

  23(632)=3

Explanation of Solution

Given information:

An expression is given as 23(632) .

Formula used:

Difference of two fraction ab and cd can be performed by

  abcd=abcbbd

Product of two fraction ab and cd can be performed by

  abcd=acbd

Calculation:

Consider the given expression.

  23(632)

Now, simplify the expression as shown:

  23(632)=232632=231292=2392=3

Here, the simplified value is 3 .

(b)

To determine

To find: the simplest value of 0.25(89+12) .

Expert Solution

Answer to Problem 27E

  0.25(89+12)=2572

Explanation of Solution

Given information:

An expression is given as 0.25(89+12) .

Formula used:

Sum of two fraction ab and cd can be performed by

  ab+cd=ab+cbbd

Product of two fraction ab and cd can be performed by

  abcd=acbd

Calculation:

Consider the given expression.

Now, simplify the expression as shown:

  0.25(89+12)=0.2528+992=0.2516+918=0.252518=2572

Here, the simplified value is 2572 .

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