# the difference quotient for the given function.

### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

#### Solutions

Chapter 1.1, Problem 28E
To determine

Expert Solution

## Answer to Problem 28E

The answerof the function is 1x+1

### Explanation of Solution

Given information:

The given function is,

f(x)=x+3x+1

Concept used:

To represent the function:

A function f is a rule that assigns to each element x in a set D exactly one element called f(x) in a set E

The given function is,

f(x)=x+3x+1

Calculate f(1) for x in the given function f(x)=x+3x+1 ,

f(1)=1+31+1=42=2

And f(x)=x+3x+1

All values of f(1) and f(x) stand in f(x)f(1)x1

f(x)f(1)x1=x+3x+12x1=x+32x2x+1x1=1xx+1×1x1=1x+1

Therefore,the answer of the function is 1x+1

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