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# Find the gauge and absolute pressures in the balloon and peanut jar shown in Figure 11.16, assuming the manometer connected to the balloon uses water whereas the manometer connected to the jar contains mercury. Express in units of centimeters of water for the balloon and millimeters of mercury for the jar, taking h = 0.0500 m for each. Figure 11.16 An open-tube manometer has one side open to the atmosphere. (a) Fluid depth must be the same on both sides, or the pressure each side exerts at the bottom will be unequal and there will be flow from the deeper side. (b) A positive gauge pressure P g = h ρ g transmitted to one side of the manometer can support a column of fluid of height h. (c) Similarly, atmospheric pressure is greater than a negative gauge pressure P g by an amount h ρ g .The jar's rigidity prevents atmospheric pressure from being transmitted to the peanuts.

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### College Physics

1st Edition
Paul Peter Urone + 1 other
Publisher: OpenStax College
ISBN: 9781938168000

#### Solutions

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Section
BuyFindarrow_forward

### College Physics

1st Edition
Paul Peter Urone + 1 other
Publisher: OpenStax College
ISBN: 9781938168000
Chapter 11, Problem 29PE
Textbook Problem
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## Find the gauge and absolute pressures in the balloon and peanut jar shown in Figure 11.16, assuming the manometer connected to the balloon uses water whereas the manometer connected to the jar contains mercury. Express in units of centimeters of water for the balloon and millimeters of mercury for the jar, taking h = 0.0500 m for each. Figure 11.16 An open-tube manometer has one side open to the atmosphere. (a) Fluid depth must be the same on both sides, or the pressure each side exerts at the bottom will be unequal and there will be flow from the deeper side. (b) A positive gauge pressure P g = h ρ g transmitted to one side of the manometer can support a column of fluid of height h. (c) Similarly, atmospheric pressure is greater than a negative gauge pressure P g by an amount h ρ g .The jar's rigidity prevents atmospheric pressure from being transmitted to the peanuts.

To determine

The gauge and absolute pressures in the balloon and peanut jar shown in Figure, assuming the manometer connected to the balloon uses water whereas the manometer connected to the jar contains mercury? Express in units of centimeters of water for the balloon and millimeters of mercury for the jar, taking h = 0.0500 m for each.

### Explanation of Solution

Given info:

h=0.0500m

Formula used:

Pressure,

P=hρg , h is the height, ρ is the density and g is acceleration due to gravity.

Absolute pressure,

Pabs=Pg+Patm

Calculation:

Balloon

Pabs=Pg+PatmPg=0.0500 m of H2O     = 5 cm of H2OPabs=(0.0500+1013251000×9.81)=10.38 m of H2O      = 1.038×103cm of H2O

Peanut jar

Pabs=Pg+PatmPg=0

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