# the statement “ x is positive” in terms of inequality. ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.1, Problem 37E

(a)

To determine

## To write: the statement “ x is positive” in terms of inequality.

Expert Solution

x>0

### Explanation of Solution

Given information:

x is positive

Calculation:

Consider the given statement.

x is positive

Now, positive number is always greater than 0.

So, x>0 .

(b)

To determine

Expert Solution

t<4

### Explanation of Solution

Given information:

t is less than 4

Calculation:

Consider the given statement.

t is less than 4

Now, less than sign is '<' .

So, t is less than 4, in terms of an inequality can be written as

t<4 .

(c)

To determine

Expert Solution

aπ

### Explanation of Solution

Given information:

a is greater than or equal to π .

Calculation:

Consider the given statement.

a is greater than or equal to π

Now, greater than equal sign is '' .

So, a is greater than or equal to π , in terms of an inequality can be written as

aπ .

(d)

To determine

Expert Solution

5<x<13

### Explanation of Solution

Given information:

x is greater than 5 and less than 13 .

Calculation:

Consider the given statement.

x is greater than 5 and less than 13

Now, greater than sign is '>' and less than symbol is '<' .

So, x is greater than 5 and less than 13 , in terms of an inequality can be written as

5<x<13 .

(e)

To determine

Expert Solution

|p3|5

### Explanation of Solution

Given information:

The distance between p and 3 is at most 5 .

Calculation:

Consider the given statement.

The distance between p and 3 is at most 5 .

Distance between two points a and b can be written as

d(a,b)=|ab|

Now, for the word “at most” the required symbol is '' .

So, the distance between p and 3 is at most 5 , in terms of an inequality can be written as

d(p,3)5|p3|5 .

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