   Chapter 11, Problem 37GQ

Chapter
Section
Textbook Problem

Mercury and many of its compounds are dangerous poisons if breathed, swallowed, or even absorbed through the skin. The liquid metal has a vapor pressure of 0.00169 mm Hg at 24 °C. If the air in a small room is saturated with mercury vapor, how many atoms of mercury vapor occur per cubic meter?

Interpretation Introduction

Number of atoms of mercury vapor occur per cubic meter has to be identified.

Concept Introduction:

According to ideal gas equation

nTPV = RnTPPV = nRT

Where,

n = molesofgasP = pressureT = temperatureR = gas constant

Explanation

Given,

Pressure=0.00169mmHg=0.00169mmHg×1atm760mmHg=2.22×10-6atmTemperature=24oC=(24+273)=297KVolume=1m3

Use equation PV=nRT

Substituting the values in above equation as

(2.22×10-6atm)×1m3=n×(8.2057×105m3atmK1mol1)×297Kn=(2.22×10-6atm)×1m3(8

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