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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Substance A has twice the specific heat of substance B. Equal masses of the two substances, at different temperatures, are placed in thermal contact and allowed lo come to equilibrium. (a) What is the ratio QB/QA of the energy transferred to (or from) the samples? (Hint: Remember to include the correct signs.) (b) What is the ratio ΔTBTA of their temperature changes?

(a)

To determine
The ratio QB/QA of the energy transferred.

Explanation

Given Info: Substance A has twice the specific heat of substance B. Mass of substance A is equal to the mass of substance B, temperature of A is equal to the temperature of B.

Formula to calculate the heat transfer to substance A is,

QA=mAcA(TfTiA) (I)

  • QA is the heat transfer of substance A,
  • mA is the mass of substance A,
  • cA is the specific heat capacity of substance A,
  • TiA is the initial temperature of substance A,
  • Tf is the final temperature,

Formula to calculate the heat transfer to substance B is,

QB=mBcB(TfTiB) (II)

  • QB is the heat transfer of substance B,
  • mB is the mass of substance B,
  • cB is the specific heat capacity of substance B,
  • TiB is the initial temperature of substance B,

Use mAcA(TfTiA) for QA and mBcB(TfTiB) for QB in QA=QB

(b)

To determine
The ratio ΔTB/ΔTA of the energy transferred.

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