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A gas is originally in a 3.0-L container at a given temperature and pressure. The gas is transferred into a 6.0-L container and its temperature (in kelvins) is doubled. What is the net effect on the pressure? a. The pressure increases by a factor of 2. b. The pressure increases by a factor of 4. c. The pressure decreases by a factor of 4. d. The pressure remains constant.

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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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Section
BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 11, Problem 3SC
Textbook Problem
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A gas is originally in a 3.0-L container at a given temperature and pressure. The gas is transferred into a 6.0-L container and its temperature (in kelvins) is doubled. What is the net effect on the pressure?

a. The pressure increases by a factor of 2.

b. The pressure increases by a factor of 4.

c. The pressure decreases by a factor of 4.

d. The pressure remains constant.

Interpretation Introduction

Interpretation:

The effect on pressure when the temperature and volume become twice, is to be determined.

Concept introduction:

According to combined gas law, which simply combines Boyle’s Law and Charles Law to understand the effect of volume, temperature and pressure together as follows:

P1V1T1 = P2V2T2

Here P1, T1 and V1  are the initial pressure, temperature and volume and P2, T2 and V2 are the final pressure, temperature and volume of the gas.

Explanation of Solution

Given information: At P1 and T1, V1= 3L, and at P2, V2= 6L and T2=2T1

Reason for correct option:

According to the combined gas law, the relation between volume, pressure and temperature of ideal gas is as follows:

P1V1T1 = P2V2T2

Substitute V1= 3L, V2= 6L and T2=2T1 in above expression as follows:

P1

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Chemistry In Focus
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