# A gas is originally in a 3.0-L container at a given temperature and pressure. The gas is transferred into a 6.0-L container and its temperature (in kelvins) is doubled. What is the net effect on the pressure? a. The pressure increases by a factor of 2. b. The pressure increases by a factor of 4. c. The pressure decreases by a factor of 4. d. The pressure remains constant.

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

Chapter
Section

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 11, Problem 3SC
Textbook Problem
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## A gas is originally in a 3.0-L container at a given temperature and pressure. The gas is transferred into a 6.0-L container and its temperature (in kelvins) is doubled. What is the net effect on the pressure?a. The pressure increases by a factor of 2.b. The pressure increases by a factor of 4.c. The pressure decreases by a factor of 4.d. The pressure remains constant.

Interpretation Introduction

Interpretation:

The effect on pressure when the temperature and volume become twice, is to be determined.

Concept introduction:

According to combined gas law, which simply combines Boyle’s Law and Charles Law to understand the effect of volume, temperature and pressure together as follows:

P1V1T1 = P2V2T2

Here P1, T1 and V1  are the initial pressure, temperature and volume and P2, T2 and V2 are the final pressure, temperature and volume of the gas.

### Explanation of Solution

Given information: At P1 and T1, V1= 3L, and at P2, V2= 6L and T2=2T1

Reason for correct option:

According to the combined gas law, the relation between volume, pressure and temperature of ideal gas is as follows:

P1V1T1 = P2V2T2

Substitute V1= 3L, V2= 6L and T2=2T1 in above expression as follows:

P1

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