# The pressure in Denver, Colorado, is approximately 0.95 atm. Convert that to the following: a . torr b . mm Hg c . in . Hg d . psi e . N/m 2

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

Chapter
Section

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 11, Problem 40E
Textbook Problem
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## The pressure in Denver, Colorado, is approximately 0.95 atm. Convert that to the following: a . torr b . mm Hg c . in . Hg d . psi e . N/m 2

Interpretation Introduction

Interpretation:

The conversion of 0.95 atm into the given units is to be represented.

Concept Introduction:

Pressure is a physical quantity that can be measured in different units based on the metric system or SI system.

Unit conversion is defined as the process, in which multiple steps are there, that is used to convert the unit of measurement for the same given quantity. It is determined by multiplying with a conversion factor.

The fraction in which the numerator and the denominator are the same quantities, but are determined in different units is known as theconversion factor.

### Explanation of Solution

(a) Torr

The conversion of atm into torr is as follows:

1 atm=760 torr

To convert atm into torr, multiply atm by 760torratm, which is a conversion factor.

Pressure in torr = 0.95 atm×760torratm=7.2×102 torr

Hence, the pressure in torr is 7.2×102 torr.

(b) mm Hg

The conversion of atm into mm Hg is as follows:

1 atm=760.0 mm Hg

Convert atm into mm Hg by multiplying atm by 760mm Hgatm, which is a conversion factor.

Pressure in mm Hg = 0.95atm×760mm Hgatm=7.2×102 mm Hg

Thus, the pressure in mm Hg is 7.2×102 mm Hg.

c) In. Hg.

The conversion of atm into in. Hg is as follows:

1 atm = 29.92 in. Hg

To convert atm into in. Hg, multiply atm by 29.92in. Hgatm, which is a conversion factor.

Pressure in in. Hg = 0.95atm×29.92 in. Hgatm=28 in

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