   Chapter 11, Problem 42P

Chapter
Section
Textbook Problem

# A glass windowpane in a home is 0.62 cm thick and has dimensions of 1.0 m × 2.0 in. On a certain day, the indoor temperature is 25°C and the outdoor temperature is 0°C. (a) What is the rate at which energy is transferred by heat through the glass? (b) How much energy is lost through the window in one day, assuming the temperatures inside and outside remain constant?

(a)

To determine
The rate at which energy is transferred by heat through the glass.

Explanation

Given info: Thickness of the windowpane is 0.62 cm, the length of the windowpane is 1.0m and the breadth is 2.0 m, the indoor temperature is 25°C , and the outdoor temperature is 0°C .

Formula to calculate the rate at which energy is transferred is,

P=kA(ThTc)L

• P is the rate of energy transfer,
• k is the thermal conductivity of glass,
• A is the area of the glass,
• Th is hot temperature,
• Tc is cold temperature,
• L is the thickness of the windowpane,

Formula to calculate the area of the windowpane is,

A=lb

• l is the length of the windowpane,
• b is the breath of the windowpane,

Use lb for A in P=kA(ThTc)L to rewrite P.

P=k(lb)(ThTc)L

Substitute 0

(b)

To determine
The amount of energy lost in one day.

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