   Chapter 11, Problem 52P

Chapter
Section
Textbook Problem

A granite ball of radius 2.00 m and emissivity 0.450 is heated to 135°C. (a) Convert the given temperature to Kelvin. (b) What is the surface area of the ball? (c) If the ambient temperature is 25.0°C, what net power does the ball radiate?

(a)

To determine
The given temperature in Kelvin.

Explanation

Given info: Given temperature is at 135°C .

Formula to convert temperature from Celsius to Kelvin is,

TK=TC+273.15

• TK is the temperature in Kelvin,
• TC is the temperature in Celsius,

Substitute 135 for TC in above equation to convert temperature in Kelvin

(b)

To determine
The surface area of the ball.

(c)

To determine
The net power the ball radiate.

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