   Chapter 11, Problem 58AP

Chapter
Section
Textbook Problem

The surface area of an unclothed person is 1.50 m2, and his skin temperature is 33.0°C. The person is located in a dark room with a temperature of 20.0°C, and the emissivity of the skin is e = 0.95. (a) At what rate is energy radiated by the body? (b) What is the significance of the sign of your answer?

(a)

To determine
The rate of energy radiated by the body.

Explanation

Given Info: The surface area of the skin is 1.50m2 , Temperature of the skin 33.0°C , Temperature of the room 20.0°C , emissivity of the skin 0.95.

Formula to calculate the net power radiated is,

P=σAe(T4T04)

• P is power radiated from the skin,
• σ is Stefan-Boltzmann constant,
• e is the emissivity of the skin,
• T is the skin temperature,
• T0 is the room temperature,

Substitute 5.6696×108W/m2K4 for σ , 1.50m2 for A , 0.95 for e , 33.0°C for T , 20.0°C for T0 to find P

(b)

To determine
The significance of the sign of your answer.

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