BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.1, Problem 58E

a)

To determine

To express: the given graph in interval notation.

Expert Solution

Answer to Problem 58E

In terms of interval the setcan be expressed as 1y1y3 [0,2) .

Explanation of Solution

Given information:

Agraphis given as

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.1, Problem 58E , additional homework tip  1

Concept used:

Aninequality a<x<b in terms of an interval can be expressed as

  (a,b) .

Aninequality axb in terms of an interval can be expressed as [a,b] .

Aninequality ax<b in terms of an interval can be expressed as [a,b) .

Aninequality a<xb in terms of an interval can be expressed as (a,b] .

Aninequality xb in terms of an interval can be expressed as (,b] .

Aninequality x<b in terms of an interval can be expressed as (,b) .

Aninequality xa in terms of an interval can be expressed as [a,) .

Aninequality x>a in terms of an interval can be expressed as (a,) .

If the terminal number or point is included in the interval it can be represented by closed ball on the number line otherwise it will be represented by a open ball.

Calculation:

Consider the given graph.

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.1, Problem 58E , additional homework tip  2

Here, for 0 closed ball is placed on the number line, for 2 open ball is placed, so 0 will be included to the interval and 2 is not included in the set.

So, the set can be expressed as aninterval as [0,2) .

b)

To determine

To express: the given graph in interval notation.

Expert Solution

Answer to Problem 58E

In terms of interval the set can be expressed as (2,0] .

Explanation of Solution

Given information:

A graph is given as

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.1, Problem 58E , additional homework tip  3

Concept used:

Aninequality a<x<b in terms of an interval can be expressed as (a,b) .

Aninequality axb in terms of an interval can be expressed as [a,b] .

Aninequality ax<b in terms of an interval can be expressed as [a,b) .

Aninequality a<xb in terms of an interval can be expressed as (a,b] .

Aninequality xb in terms of an interval can be expressed as (,b] .

Aninequality x<b in terms of an interval can be expressed as (,b) .

Aninequality xa in terms of an interval can be expressed as [a,) .

Aninequality x>a in terms of an interval can be expressed as (a,) .

If the terminal number or point is included in the interval it can be represented by closed ball on the number line otherwise it will be represented by a open ball.

Calculation:

Consider the given graph.

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.1, Problem 58E , additional homework tip  4

Here, for 2 open ball is placed on the number line, for 0 closed ball is placed, so 0 will be included to the interval and 2 is not included in the set.

So, the set can be expressed as aninterval as (2,0] .

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