   # A pressure cooker (a kitchen appliance) is a pot on which the top seals tightly, allowing pressure to build up inside. You put water in the pot and heat it to boiling. At the higher pressure, water boils at a higher temperature, and this allows food to cook at a faster rate. Most pressure cookers have a setting of 15 psi, which means that the pressure in the pot is 15 psi above atmospheric pressure (1 atm = 14.70 psi). Use the Clausius–Clapeyron equation to calculate the temperature at which water boils in the pressure cooker. ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 11, Problem 63SCQ
Textbook Problem
181 views

## A pressure cooker (a kitchen appliance) is a pot on which the top seals tightly, allowing pressure to build up inside. You put water in the pot and heat it to boiling. At the higher pressure, water boils at a higher temperature, and this allows food to cook at a faster rate. Most pressure cookers have a setting of 15 psi, which means that the pressure in the pot is 15 psi above atmospheric pressure (1 atm = 14.70 psi). Use the Clausius–Clapeyron equation to calculate the temperature at which water boils in the pressure cooker.

Interpretation Introduction

Interpretation:

The temperature at which water boils inside the pressure cooker has to be given.

Concept Introduction:

Clausius-Clapeyron equation:

lnP=(ΔvapH0RT)+C

From this relationship we can calculate the molar enthalpy of vaporization by knowing the corresponding temperature and pressure values.

If we have pressures at two different temperatures, then enthalpy of vaporization can be calculated by

lnP2p1=-ΔvapH0R[1T2-1T1]

Boiling point of a liquid: The temperature at which external pressure and vapour pressure of the liquid become same.

Normal boiling point: When the external pressure is 760mmHg we can call it as normal boiling point.

### Explanation of Solution

Given:

Pressureinsidethepot=15psiΔvapH0=40700J/mol

Given that pressure inside cooker is 15psi above atmospheric pressure.

Therefore,

Here P2=15psi+14.7psi=29.7psi=2.02atmT1=boilingpointofwater=373K

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