   Chapter 11, Problem 76E

Chapter
Section
Textbook Problem

# A 0.15-g sample of a purified protein is dissolved in water to give 2.0 mL of solution. The osmotic pressure is found to be 18.6 torr at 25°C. Calculate the protein’s molar mass.

Interpretation Introduction

Interpretation: Molar mass of the Protein to be calculated.

Concept introduction

Molar mass can be written as mass of given substance divided by amount of the substance.

Molar mass = Mass of the given substanceamount of substance

Explanation

Record the given data

Amount of purified Protein = 0.15g

Amount of solution in which Protein dissolved = 2.0 mL

Osmotic pressure of the solution = 18.6 torr

Temperature = 25°C

To calculate molarity of Protein.

25°C = 298K

π = MRT

π =18.6torr ×1atm760 torr= M×0.08206Kmol× 298K

M=1.00×10-3mol/L

To calculate molar mass of Protein

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