Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Question
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Chapter 1.1, Problem 87E

a.

To determine

Calculate the years in which the sales showed the great increase and greatest decrease by seeing the slope.

a.

Expert Solution
Check Mark

Answer to Problem 87E

The greatest increase is $ 11.431 billion and the greatest decrease is $ 954 million .

Explanation of Solution

Given: It is given in the question that the graph shows the sales y (in billions of dollars) of the Coca − cola Company each year x from 2005 through 2012 and the graph is shown below:

  Precalculus with Limits: A Graphing Approach, Chapter 1.1, Problem 87E , additional homework tip  1

Concept Used:

In this , use the concept of graph analysis that how to read the graph data and by this calculate the question.

Calculation: Firstly , take the each year and calculate the slope and by this we easily get the lowest and the greatest.

    YEARSSLOPE

      20052006

      24.08823.104=0.984

      20062007

      28.85724.088=4.769

      20072008

      3194428.857=3.087

      20082009

      30.99031.944=0.954

      20092010

      35.12330.990=4.133

      20102011

      46.55435.123=11.431

      20112012

      48.01746.554=1.463

So , by seeing the table we find that the greatest increase was $ 11.431 billion from 20102011 .

The greatest decrease was $ 954 million from 20082009 .

Conclusion:

The greatest increase is $ 11.431 billion and the greatest decrease is $ 954 million .

b.

To determine

Calculate the equation of the line between the years 2005 and 2012 .

b.

Expert Solution
Check Mark

Answer to Problem 87E

The equation of the line between the years is y=3.559x+5.309 .

Explanation of Solution

Given: It is given in the question that the graph shows the sales y (in billions of dollars) of the Coca − cola Company each year x from 2005 through 2012 and the graph is shown below:

  Precalculus with Limits: A Graphing Approach, Chapter 1.1, Problem 87E , additional homework tip  2

Concept Used:

In this , use the concept of slope formula and point slope form the formula used is yy1=m(xx1) .

Calculation:

By using the points (5,23.104) and (12,48.017) ,

The slope is m=y2y1x2x1=48.01723.104125=3.559

Now, using the point slope form to get the equation:

  yy1=m(xx1)y23.104=3.559(x5)y23.104=3.559x17.795y=3.559x+5.309

Conclusion:

The equation is y=3.559x+5.309 .

c.

To determine

Identify the meaning of the slope of the line grom part (b) in the context of the problem.

c.

Expert Solution
Check Mark

Answer to Problem 87E

The slope in the equation means that there was an average increase in sales of about $3.559 billion.

Explanation of Solution

Given: It is given in the question that the graph shows the sales y (in billions of dollars) of the Coca − cola Company each year x from 2005 through 2012 and the graph is shown below:

  Precalculus with Limits: A Graphing Approach, Chapter 1.1, Problem 87E , additional homework tip  3

Concept Used:

In this, use the concept to read and understand the equation and get the answer from it.

Calculation: The equation that get from part (b) is y=3.559x+5.309 .

From the equation it is concluded that there was an average increase in sales of about $3.559 billion from 2005to2012 .

Conclusion:

It is conclude that the average sales is $3.559 .

d.

To determine

Find the sales of the Coca − cola company in 2017 by using the equation from part (b).Find whether it is accurate or not,give reason.

d.

Expert Solution
Check Mark

Answer to Problem 87E

The approximate sales of the Coca − Cola Company in 2017 is $65.812 .It is not accurate.

Explanation of Solution

Given: It is given in the question that the graph shows the sales y (in billions of dollars) of the Coca − cola Company each year x from 2005 through 2012 and the graph is shown below:

  Precalculus with Limits: A Graphing Approach, Chapter 1.1, Problem 87E , additional homework tip  4

Concept Used:

In this, use the concept of putting the value in the equation and finding the answer.

Calculation: Here, in part (b) the equation will be y=3.559x+5.309 .

Now ,put x=17 in the equation to get some approximate value of sales,

  y=3.559x+5.309y=3.559(17)+5.309y=60.503+5.309y=65.812

It is not the accurate sale as the seasonal changes may affect the sale of the product.

Conclusion:

The approximate sales in 2017 is $65.812 .

Chapter 1 Solutions

Precalculus with Limits: A Graphing Approach

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Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.6 - Prob. 20ECh. 1.6 - Prob. 21ECh. 1.6 - Prob. 22ECh. 1.6 - Prob. 23ECh. 1.6 - Prob. 24ECh. 1.6 - Prob. 25ECh. 1.6 - Prob. 26ECh. 1.6 - Prob. 27ECh. 1.6 - Prob. 28ECh. 1.6 - Prob. 29ECh. 1.6 - Prob. 30ECh. 1.6 - Prob. 31ECh. 1.6 - Prob. 32ECh. 1.6 - Prob. 33ECh. 1.6 - Prob. 34ECh. 1.6 - Prob. 35ECh. 1.6 - Prob. 36ECh. 1.6 - Prob. 37ECh. 1.6 - Prob. 38ECh. 1.6 - Prob. 39ECh. 1.6 - Prob. 40ECh. 1.6 - Prob. 41ECh. 1.6 - Prob. 42ECh. 1.6 - Prob. 43ECh. 1.6 - Prob. 44ECh. 1.6 - Prob. 45ECh. 1.6 - Prob. 46ECh. 1.6 - Prob. 47ECh. 1.6 - Prob. 48ECh. 1.6 - Prob. 49ECh. 1.6 - Prob. 50ECh. 1.6 - Prob. 51ECh. 1.6 - Prob. 52ECh. 1.6 - Prob. 53ECh. 1.6 - Prob. 54ECh. 1.6 - Prob. 55ECh. 1.6 - Prob. 56ECh. 1.6 - Prob. 57ECh. 1.6 - Prob. 58ECh. 1.6 - Prob. 59ECh. 1.6 - Prob. 60ECh. 1.6 - Prob. 61ECh. 1.6 - Prob. 62ECh. 1.6 - Prob. 63ECh. 1.6 - Prob. 64ECh. 1.6 - Prob. 65ECh. 1.6 - Prob. 66ECh. 1.6 - Prob. 67ECh. 1.6 - Prob. 68ECh. 1.6 - Prob. 69ECh. 1.6 - Prob. 70ECh. 1.6 - Prob. 71ECh. 1.6 - Prob. 72ECh. 1.6 - Prob. 73ECh. 1.6 - Prob. 74ECh. 1.6 - Prob. 75ECh. 1.6 - Prob. 76ECh. 1.6 - Prob. 77ECh. 1.6 - Prob. 78ECh. 1.6 - Prob. 79ECh. 1.6 - Prob. 80ECh. 1.6 - Prob. 81ECh. 1.6 - Prob. 82ECh. 1.6 - Prob. 83ECh. 1.6 - Prob. 84ECh. 1.6 - Prob. 85ECh. 1.6 - Prob. 86ECh. 1.6 - Prob. 87ECh. 1.6 - Prob. 88ECh. 1.6 - Prob. 89ECh. 1.6 - Prob. 90ECh. 1.6 - Prob. 91ECh. 1.6 - Prob. 92ECh. 1.6 - Prob. 93ECh. 1.6 - Prob. 94ECh. 1.6 - Prob. 95ECh. 1.6 - Prob. 96ECh. 1.6 - Prob. 97ECh. 1.6 - Prob. 98ECh. 1.6 - Prob. 99ECh. 1.6 - Prob. 100ECh. 1.6 - Prob. 101ECh. 1.6 - Prob. 102ECh. 1.6 - Prob. 103ECh. 1.6 - Prob. 104ECh. 1.6 - Prob. 105ECh. 1.6 - Prob. 106ECh. 1.6 - Prob. 107ECh. 1.6 - Prob. 108ECh. 1.6 - Prob. 109ECh. 1.6 - Prob. 110ECh. 1.6 - Prob. 111ECh. 1.6 - Prob. 112ECh. 1.6 - Prob. 113ECh. 1.6 - Prob. 114ECh. 1.6 - Prob. 115ECh. 1.6 - Prob. 116ECh. 1.6 - Prob. 117ECh. 1.6 - Prob. 118ECh. 1.6 - Prob. 119ECh. 1.6 - Prob. 120ECh. 1.6 - Prob. 121ECh. 1.6 - Prob. 122ECh. 1.6 - Prob. 123ECh. 1.6 - Prob. 124ECh. 1.6 - Prob. 125ECh. 1.6 - Prob. 126ECh. 1.6 - Prob. 127ECh. 1.6 - Prob. 128ECh. 1.6 - Prob. 129ECh. 1.6 - Prob. 130ECh. 1.6 - Prob. 131ECh. 1.6 - Prob. 132ECh. 1.6 - Prob. 133ECh. 1.6 - Prob. 134ECh. 1.6 - Prob. 135ECh. 1.6 - Prob. 136ECh. 1.6 - Prob. 137ECh. 1.6 - Prob. 138ECh. 1.6 - Prob. 139ECh. 1.6 - Prob. 140ECh. 1.7 - Prob. 1ECh. 1.7 - Prob. 2ECh. 1.7 - Prob. 3ECh. 1.7 - Prob. 4ECh. 1.7 - Prob. 5ECh. 1.7 - Prob. 6ECh. 1.7 - Prob. 7ECh. 1.7 - Prob. 8ECh. 1.7 - Prob. 9ECh. 1.7 - Prob. 10ECh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1.7 - Prob. 35ECh. 1.7 - Prob. 36ECh. 1.7 - Prob. 37ECh. 1.7 - Prob. 38ECh. 1 - Prob. 1RECh. 1 - Prob. 2RECh. 1 - Prob. 3RECh. 1 - Prob. 4RECh. 1 - Prob. 5RECh. 1 - Prob. 6RECh. 1 - Prob. 7RECh. 1 - Prob. 8RECh. 1 - Prob. 9RECh. 1 - Prob. 10RECh. 1 - Prob. 11RECh. 1 - Prob. 12RECh. 1 - Prob. 13RECh. 1 - Prob. 14RECh. 1 - Prob. 15RECh. 1 - Prob. 16RECh. 1 - Prob. 17RECh. 1 - Prob. 18RECh. 1 - Prob. 19RECh. 1 - Prob. 20RECh. 1 - Prob. 21RECh. 1 - Prob. 22RECh. 1 - Prob. 23RECh. 1 - Prob. 24RECh. 1 - Prob. 25RECh. 1 - Prob. 26RECh. 1 - Prob. 27RECh. 1 - Prob. 28RECh. 1 - Prob. 29RECh. 1 - Prob. 30RECh. 1 - Prob. 31RECh. 1 - Prob. 32RECh. 1 - Prob. 33RECh. 1 - Prob. 34RECh. 1 - Prob. 35RECh. 1 - Prob. 36RECh. 1 - Prob. 37RECh. 1 - Prob. 38RECh. 1 - Prob. 39RECh. 1 - Prob. 40RECh. 1 - Prob. 41RECh. 1 - Prob. 42RECh. 1 - Prob. 43RECh. 1 - Prob. 44RECh. 1 - Prob. 45RECh. 1 - Prob. 46RECh. 1 - Prob. 47RECh. 1 - Prob. 48RECh. 1 - Prob. 49RECh. 1 - Prob. 50RECh. 1 - Prob. 51RECh. 1 - Prob. 52RECh. 1 - Prob. 53RECh. 1 - Prob. 54RECh. 1 - Prob. 55RECh. 1 - Prob. 56RECh. 1 - Prob. 57RECh. 1 - Prob. 58RECh. 1 - Prob. 59RECh. 1 - Prob. 60RECh. 1 - Prob. 61RECh. 1 - Prob. 62RECh. 1 - Prob. 63RECh. 1 - Prob. 64RECh. 1 - Prob. 65RECh. 1 - Prob. 66RECh. 1 - Prob. 67RECh. 1 - Prob. 68RECh. 1 - Prob. 69RECh. 1 - Prob. 70RECh. 1 - Prob. 71RECh. 1 - Prob. 72RECh. 1 - Prob. 73RECh. 1 - Prob. 74RECh. 1 - Prob. 75RECh. 1 - Prob. 76RECh. 1 - Prob. 77RECh. 1 - Prob. 78RECh. 1 - Prob. 79RECh. 1 - Prob. 80RECh. 1 - Prob. 81RECh. 1 - Prob. 82RECh. 1 - Prob. 83RECh. 1 - Prob. 84RECh. 1 - Prob. 85RECh. 1 - Prob. 86RECh. 1 - Prob. 87RECh. 1 - Prob. 88RECh. 1 - Prob. 89RECh. 1 - Prob. 90RECh. 1 - Prob. 91RECh. 1 - Prob. 92RECh. 1 - Prob. 93RECh. 1 - Prob. 94RECh. 1 - Prob. 95RECh. 1 - Prob. 96RECh. 1 - Prob. 97RECh. 1 - Prob. 98RECh. 1 - Prob. 99RECh. 1 - Prob. 100RECh. 1 - Prob. 101RECh. 1 - Prob. 102RECh. 1 - Prob. 103RECh. 1 - Prob. 104RECh. 1 - Prob. 105RECh. 1 - Prob. 106RECh. 1 - Prob. 107RECh. 1 - Prob. 108RECh. 1 - Prob. 109RECh. 1 - Prob. 110RECh. 1 - Prob. 111RECh. 1 - Prob. 112RECh. 1 - Prob. 113RECh. 1 - Prob. 114RECh. 1 - Prob. 115RECh. 1 - Prob. 116RECh. 1 - Prob. 117RECh. 1 - Prob. 118RECh. 1 - Prob. 119RECh. 1 - Prob. 120RECh. 1 - Prob. 121RECh. 1 - Prob. 122RECh. 1 - Prob. 123RECh. 1 - Prob. 124RECh. 1 - Prob. 125RECh. 1 - Prob. 126RECh. 1 - Prob. 127RECh. 1 - Prob. 128RECh. 1 - Prob. 129RECh. 1 - Prob. 130RECh. 1 - Prob. 131RECh. 1 - Prob. 132RECh. 1 - Prob. 133RECh. 1 - Prob. 134RECh. 1 - Prob. 135RECh. 1 - Prob. 136RECh. 1 - Prob. 137RECh. 1 - Prob. 138RECh. 1 - Prob. 139RECh. 1 - Prob. 140RECh. 1 - Prob. 141RECh. 1 - Prob. 142RECh. 1 - Prob. 143RECh. 1 - Prob. 144RECh. 1 - Prob. 145RECh. 1 - Prob. 146RECh. 1 - Prob. 147RECh. 1 - Prob. 148RECh. 1 - Prob. 149RECh. 1 - Prob. 150RECh. 1 - Prob. 151RECh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CT
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