Chapter 1.1, Problem 93E

To determine

To Write: the linear equation that gives dollar value of product in terms of year.

Answer to Problem 93E

  $V=290+125t$

Explanation of Solution

Given:

Product value in $2018$ is $ $2540$ and increase in rate is $ $125$ per year.

Calculation:

Let $V_{2018}$represent product value.

Let $t$ represent time in year and in the year $2018$ , time is $t=18$ .

Since, product value in year $2018$ is given therefore find product value in year $2000$ .

In $2000$ , $t=0$ .

In year $2018$ , equation for product value is

  $V_{2018}=V_{2010}+Rt$

Substituting $V_{2018}=\$2540$ , $R=125$ and $t=18$ .

  $\begin{array}{l}2540=V_{2000}+125\times 18\\ V_{2000}=2540-2250\\ V_{2000}=290\end{array}$

Linear equation in terms of $t$ is.

  $\begin{array}{l}V=V_{2000}+Rt\\ V=290+125t\end{array}$

Therefore, the answer is $V=290+125t$ .