BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.11, Problem 40E

(A)

To determine

To find:

The equation given that the statement

Expert Solution

Answer to Problem 40E

The equation is F=kws2r

Explanation of Solution

Given:

  F varies jointly as w or F is jointly proportional to wands2

Concept used:

If the quantities x , y and z are related by an equation

  z=kxy

Where k is nonzero constant

That is z varies jointly as x or z isjointly proportional to xandy

The constant k is called constant proportionality

Calculation:

If the quantities F,w and s2 and inversely as r are related by an equation

  Fαws2r

  F=kws2r

For some constant k0

That is F varies jointly as w or F is jointly proportional to wands2

The constant k is called constant proportionality

(B)

To determine

To find:

The equation of the value given that the statement

Expert Solution

Answer to Problem 40E

The speed of second car s=48mi/h

Explanation of Solution

Given:

  F varies jointly as w or F is jointly proportional to wands2

Concept used:

If the quantities x , y and z are related by an equation

  z=kxy

Where k is nonzero constant

That is z varies jointly as x or z is jointly proportional to xandy

The constant k is called constant proportionality

Calculation:

The equation of the set is w=1600lb and s=60mi/h

The force

  F1=k(1600)(60)2r

The second car inside the curve set w=2500lb in the equation

  F2=k(2500)(s)2r

Since the force is the same in both cases solve the equation

  F1=F2k(1600)(60)2r=k(2500)(s)2r(1600)(3600)=2500(s)2(s)2=(1600)(3600)2500(s)2=2304s=2304s=48mi/h

The speed of second car s=48mi/h

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