Concept explainers
ArrayList:
A list of object is stored in the “ArrayList”. Once an array list is created, the size of the array is fixed. Java gives the “ArrayList” class for storing an unlimited number of objects in a single list.
Creation of ArrayList:
ArrayList <String> x = new ArrayList<String>();
The above statement is an example of creation of “ArrayList”. The array object “x” is used to store the list of objects.
Explanation of Solution
Reason for not removing all the “Dallas” in the list:
“No”, the given code is not correctly removes all the elements in the arrayList.
Justification:
In the above sub part code,
- The variable “i” becomes “1” after removing one “Dallas” in the list and the variable “i” becomes “2” after removing two “Dallas” in the list. Then, the check the condition “2 < 2”. But it fails. So, the loop will end after removing two elements.
- Hence, the given code is correctly not removes all the elements in the arrayList. Because, the final array list contains “{“Houston”, “Dallas”}”.
Corrected code:
//Import the java package
import java.util.*;
//Define the class
public class Sample
{
//Define the main() method
public static void main(String[] args) throws Exception
{
//Declare the array list
ArrayList<String> list = new ArrayList<String>();
//Call add() method to add the string into list
list.add("Dallas");
list.add("Houston");
list.add("Dallas");
list.add("Dallas");
/*Check whether "i" is less than size of array list. */
for (int i = 0; i < list.size(); i++)
{
/*Check whether the condition is true. That is, removing the element from list by calling the remove() method. */
if(list.remove("Dallas"))
{
//Decrement the "i" value
i--;
/*Display the remaining elements in array list. */
System.out.println(list);
}
}
}
}
Explanation:
In the above code,
- Declare the array list in the name of “list”...
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