Probability and Statistics for Engineering and the Sciences
Probability and Statistics for Engineering and the Sciences
9th Edition
ISBN: 9781305251809
Author: Jay L. Devore
Publisher: Cengage Learning
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Chapter 11.3, Problem 37E
To determine

Perform ANOVA to test the significance at 1% level of significance.

Expert Solution & Answer
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Answer to Problem 37E

The ANOVA for the given data is shown below:

Source

Degrees of

freedom

Sum of

squares

Mean sum of

squares

F-ratio

Fabric

A

24,414.6582207.3292259.293

Type of exposure

B

147.25547.25548.36745

Degree of exposure

C

2983.566491.783503.3603

Fabric direction

D

10.0440.0440.045036
Interaction AB230.60615.30315.66325
Interaction AC21,101.754275.446281.9304
Interaction AD20.940.470.481064
Interaction BC24.2822.1412.191402
Interaction BD10.2730.2730.279427
Interaction CD20.4940.2470.252815
Interaction ABC414.8563.7143.801433
Interaction ABD28.1444.0724.167861

Interaction

ACD

43.0680.7670.785056

Interaction

BCD

20.560.280.286592
Interaction ABCD41.3890.3470.355
Error3635.1720.977
Total716,647.0919.621

There is sufficient of evidence to conclude that there is an effect of fabric on the extent of color change at 1% level of significance.

There is sufficient of evidence to conclude that there is an effect exposure type on the extent of color change at 1% level of significance.

There is sufficient of evidence to conclude that there is an effect of exposure level on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an effect of fabric direction on the extent of color change at 1% level of significance.

There is sufficient of evidence to conclude that there is an interaction effect of fabric and exposure type on the extent of color change at 1% level of significance.

There is sufficient of evidence to conclude that there is an interaction effect of fabric and exposure level on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of fabric and fabric direction on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of exposure type and exposure level on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of exposure type and fabric direction on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of exposure level and fabric direction on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure type and exposure level on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure type and fabric direction on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure level and fabric direction on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of exposure type, exposure level and fabric direction on the extent of color change at 1% level of significance.

There is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure type, exposure level and fabric direction on the extent of color change at 1% level of significance.

Explanation of Solution

Given info:

An experiment was conducted to test the effect of fabric, type of exposure, level of exposure and fabric direction on the color change of the fabric. Two observation were noted for each of the four factors.

Calculation:

The general ANOVA table is given below:

SourceDegrees of freedomSum of squaresMean sum of squaresF-ratio
Factor AI1SSA=ijkp(X¯iX¯)2MSA=SSA(I1)fA=MSAMSE
Factor BJ1SSB=ijkp(X¯jX¯)2MSB=SSB(J1)fB=MSBMSE
Factor CK1SSC=ijkp(X¯kX¯)2MSC=SSC(K1)fC=MSCMSE
Factor DP1SSD=ijkp(X¯PX¯)2MSD=SSC(P1)fC=MSCMSE
Interaction AB(I1)(J1)SSAB=KPLij(X¯ijX¯iX¯jX¯p+X¯)2MSAB=SSAB(I1)(J1)fAB=MSABMSE
Interaction ABC(I1)(J1)(K1)SSABC=Lijk(X¯ijkX¯ijX¯ikX¯jk+X¯i+X¯j+X¯kX¯)2MSABC=SSABC(I1)(J1)(K1)fABC=MSABCMSE
ErrorIJPK(L1)SSE=ijkpl(XijkplX¯ijkp)2MSE=SSEIJK(L1)
TotalIJKPL1SST=ijkpl(XijkplX¯)2

The sum of squares for each factor and interaction is calculated by multiplying the mean sum of squares with its corresponding degrees of freedom.

Sum of squares excluding ABCD:

SourceSum of squares
A4,414.658
B47.255
C983.566
D0.044
AB30.606
AC1,101.784
AD0.94
BC4.282
BD0.273
CD0.494
ABC14.856
ABD8.144
ACD3.068
BCD0.56
Error35.172
Total6,647.091

Using the above table SSABCD can be calculated:

SST=[SSA+SB+SSC+SSD+SSAB+SSAC+SSAD+SSBC+SSCD+SSABC+SSABD+SSACD+SSBCD+SSABCD]SSABCD=SST[SSA+SB+SSC+SSD+SSAB+SSAC+SSAD+SSBC+SSCD+SSABC+SSABD+SSACD+SSBCD+SSABCD]=6,647.091[4,414.658+47.255+983.566+0.044+30.606+1,101.784+0.94+4.282+0.273+0.494+14.856+8.144+3.068+0.56+35.172]=6,647.0916,645.702

=1.389

The mean sum of squares for the interaction ABCD is given below:

MSABCD=SSABCD(I1)(J1)(K1)(P1)=1.389(31)(21)(31)(21)=1.389(2)(1)(2)(1)=1.3894

                 =0.347

Thus, the mean sum of squares for the interaction ABCD is 0.347.

The ANOVA for the given data is shown below:

SourceDegrees of freedom

Sum of

squares

Mean sum of

squares

F-ratio

Fabric

A

31=24,414.6582207.3292,259.293

Type of

exposure

B

21=147.25547.25548.36745

Degree of

exposure

C

31=2983.566491.783503.3603

Fabric

direction

D

21=10.0440.0440.045036

Interaction

AB

(31)(21)=230.60615.30315.66325

Interaction

AC

(21)(31)=21,101.754275.446281.9304

Interaction

AD

(31)(21)=20.940.470.481064

Interaction

BC

(21)(31)=24.2822.1412.191402

Interaction

BD

(21)(21)=10.2730.2730.279427

Interaction

CD

(31)(21)=20.4940.2470.252815

Interaction

ABC

(31)(21)(31)=414.8563.7143.801433

Interaction

ABD

(31)(21)(21)=28.1444.0724.167861

Interaction

ACD

(31)(31)(21)=43.0680.7670.785056

Interaction

BCD

(21)(31)(21)=20.560.280.286592

Interaction

ABCD

(31)(21)(31)(21)=41.3890.3470.355
Error3×2×3×2(21)=36(1)=3635.1720.977
Total3×2×3×2×21=721=716,647.0919.621

Where,

The F statistic for each factor is obtained by dividing the mean sum of squares with the mean sum of squares due to error.

Testing the main effects:

Testing the Hypothesis for the factor A:

Null hypothesis:

H0A:α1=α2=α3=0

That is, there is no significant difference in the extent of color change due to the three levels of fabrics.

Alternative hypothesis:

HaA:At least one of the αi's0

That is, there is significant difference in the extent of color change due to the three levels of fabrics.

Testing the Hypothesis for the factor B:

Null hypothesis:

H0B:β1=β2=β3=0

That is, there is no significant difference in the extent of color change due to the two levels of exposure type.

Alternative hypothesis:

HaB:At least one of the βj's0

That is, there is a significant difference in the extent of color change due to the two levels of exposure type.

Testing the Hypothesis for the factor C:

Null hypothesis:

H0C:δ1=δ2=δ3=0

That is, there is no significant difference in the extent of color change due to the three levels of exposure level.

Alternative hypothesis:

HaC:At least one of the δk's0

That is, there is a significant difference in the extent of color change due to the three levels of exposure level.

Testing the Hypothesis for the factor D:

Null hypothesis:

H0D:λ1=λ2=0

That is, there is no significant difference in the extent of color change due to the two levels of fabric direction.

Alternative hypothesis:

HaD:At least one of the λp's0

That is, there is a significant difference in the extent of color change due to the two levels of fabric direction.

Testing the Hypothesis for the interaction effect of AB:

Null hypothesis:

H0AB:γijAB's=0

That is, there is no significant difference in the extent of color change due to the interaction between fabric and exposure type.

Alternative hypothesis:

HaAB:At least one of γijAB's0

That is, there is significant difference in the extent of color change due to the interaction between fabric and exposure type.

Testing the Hypothesis for the interaction effect AC:

Null hypothesis:

H0AC:γijAC's=0

That is, there is no significant difference in the extent of color change due to the interaction between fabric and exposure level.

Alternative hypothesis:

HaAC:At least one of γijAC's0

That is, there is a significant difference in the extent of color change due to the interaction between fabric and exposure level.

Testing the Hypothesis for the interaction effect AD:

Null hypothesis:

H0AD:γijAD's=0

That is, there is no significant difference in the extent of color change due to the interaction between fabric and fabric direction.

Alternative hypothesis:

HaAD:At least one of γijAD's0

That is, there is a significant difference in the extent of color change due to the interaction between fabric and fabric direction.

Testing the Hypothesis for the interaction effect BC:

Null hypothesis:

H0BC:γijBC's=0

That is, there is no significant difference in the extent of color change due to the interaction between exposure type and exposure level.

Alternative hypothesis:

HaBC:At least one of γijBC's0

That is, there is significant difference in the extent of color change due to the interaction between exposure type and exposure level.

Testing the Hypothesis for the interaction effect BD:

Null hypothesis:

H0BD:γijBD's=0

That is, there is no significant difference in the extent of color change due to the interaction between exposure type and fabric direction.

Alternative hypothesis:

HaBD:At least one of γijBD's0

That is, there is significant difference in the extent of color change due to the interaction between exposure type and fabric direction.

Testing the Hypothesis for the interaction effect CD:

Null hypothesis:

H0CD:γijCD's=0

That is, there is no significant difference in the extent of color change due to the interaction between exposure level and fabric direction.

Alternative hypothesis:

HaCD:At least one of γijCD's0

That is, there is significant difference in the extent of color change due to the interaction between exposure level and fabric direction.

Testing the Hypothesis for the interaction effect ABC:

Null hypothesis:

H0ABC:γijkABC's=0

That is, there is no significant difference in the extent of color change due to the interaction between fabric, exposure type and exposure level.

Alternative hypothesis:

HaABC:At least one of γijkABC's0

That is, there is a significant difference in the extent of color change due to the interaction between fabric, exposure type and exposure level.

Testing the Hypothesis for the interaction effect ABD:

Null hypothesis:

H0ABD:γijkABD's=0

That is, there is no significant difference in the extent of color change due to the interaction between fabric, exposure type and fabric direction.

Alternative hypothesis:

HaABD:At least one of γijkABD's0

That is, there is a significant difference in the extent of color change due to the interaction between fabric, exposure type and fabric direction.

Testing the Hypothesis for the interaction effect ACD:

Null hypothesis:

H0ACD:γijkACD's=0

That is, there is no significant difference in the extent of color change due to the interaction between fabric, exposure level and fabric direction.

Alternative hypothesis:

HaACD:At least one of γijkACD's0

That is, there is a significant difference in the extent of color change due to the interaction between fabric, exposure level and fabric direction.

Testing the Hypothesis for the interaction effect BCD:

Null hypothesis:

H0BCD:γijkBCD's=0

That is, there is no significant difference in the extent of color change due to the interaction between exposure type, exposure level and fabric direction.

Alternative hypothesis:

HaBCD:At least one of γijkBCD's0

That is, there is a significant difference in the extent of color change due to the interaction between exposure type, exposure level and fabric direction.

Testing the Hypothesis for the interaction effect ABCD:

Null hypothesis:

H0ABCD:γijkpABCD's=0

That is, there is no significant difference in the extent of color change due to the interaction between exposure type, exposure level and fabric direction.

Alternative hypothesis:

HaABCD:At least one of γijkpABCD's0

That is, there is a significant difference in the extent of color change due to the interaction between fabric, exposure type, exposure level and fabric direction.

P-value for the main effect of A:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 2,259.29.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  1

P-value for the main effect of B:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 1 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 48.37.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  2

P-value for the main effect of C:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 503.36.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  3

P-value for the main effect of D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 1 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.05.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  4

P-value for the interaction effect of A and B:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 15.66.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  5

P-value for the interaction effect of A and C:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 4 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 281.93.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  6

P-value for the interaction effect of A and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.48.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  7

P-value for the interaction effect of B and C:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 2.19.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  8

P-value for the interaction effect of B and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 1 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.28.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  9

P-value for the interaction effect of C and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.25.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  10

P-value for the interaction effect of A, B and C:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 4 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 3.80.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  11

P-value for the interaction effect of A, B and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 4.17.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  12

P-value for the interaction effect of A, C and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 4 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.79.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  13

P-value for the interaction effect of B, C and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 2 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.29.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  14

P-value for the interaction effect of A, B, C and D:

Software procedure:

Step-by-step procedure to find the P-value is given below:

  • Click on Graph, select View Probability and click OK.
  • Select F, enter 4 in numerator df and 36 in denominator df.
  • Under Shaded Area Tab select X value under Define Shaded Area By and select right tails.
  • Choose X value as 0.355.
  • Click OK.

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 11.3, Problem 37E , additional homework tip  15

Conclusion:

For the main effect of A:

The P- value for the factor A (fabric) is 0.000 and the level of significance is 0.01.

Here, the P- value is lesser than the level of significance.

That is, 0.000(=P-value)<0.01(=α).

Thus, the null hypothesis is rejected,

Hence, there is sufficient of evidence to conclude that there is an effect of fabric on the extent of color change at 1% level of significance.

For main effect of B:

The P- value for the factor B (exposure level) is 0.000 and the level of significance is 0.01.

Here, the P- value is lesser than the level of significance.

That is, 0.000(=P-value)<0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is sufficient of evidence to conclude that there is an effect exposure type on the extent of color change at 1% level of significance.

For main effect of C:

The P- value for the factor C (exposure level) is 0.000 and the level of significance is 0.01.

Here, the P- value is lesser than the level of significance.

That is, 0.000(=P-value)<0.01(=α).

Thus, the null hypothesis is rejected.

Hence, there is sufficient of evidence to conclude that there is an effect of exposure level on the extent of color change at 1% level of significance.

For main effect of D:

The P- value for the factor D (fabric direction) is 0.8243 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.8243(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an effect of fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor A and B:

The P- value for the interaction effect AB (fabric and exposure type) is 0.000 and the level of significance is 0.01.

Here, the P- value is lesser than the level of significance.

That is, 0.000(=P-value)<0.01(=α).

Thus, the null hypothesis is rejected,

Hence, there is sufficient of evidence to conclude that there is an interaction effect of fabric and exposure type on the extent of color change at 1% level of significance.

Interaction effect of factor A and C:

The P- value for the interaction effect AC (fabric and exposure level) is 0.000 and the level of significance is 0.01.

Here, the P- value is lesser than the level of significance.

That is, 0.000(=P-value)<0.01(=α).

Thus, the null hypothesis is rejected.

Hence, there is sufficient of evidence to conclude that there is an interaction effect of fabric and exposure level on the extent of color change at 1% level of significance.

Interaction effect of factor A and D:

The P- value for the interaction effect AD (fabric and fabric direction) is 0.6227 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.6227(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of fabric and fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor B and C:

The P- value for the interaction effect BC (exposure type and exposure level) is 0.1266 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.1266(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected,

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of exposure type and exposure level on the extent of color change at 1% level of significance.

Interaction effect of factor B and D:

The P- value for the interaction effect BD (exposure type and fabric direction) is 0.5999 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.5999(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected,

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of exposure type and fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor C and D:

The P- value for the interaction effect CD (exposure level and fabric direction) is 0.7801 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.7801(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected,

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of exposure level and fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor A,B and C:

The P- value for the interaction effect ABC (fabric, exposure type and exposure level) is 0.01119 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.1119(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure type and exposure level on the extent of color change at 1% level of significance.

Interaction effect of factor A,B and D:

The P- value for the interaction effect ABD (fabric, exposure type and fabric direction) is 0.0235 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.0235(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure type and fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor A,C and D:

The P- value for the interaction effect ACD (fabric, exposure level and fabric direction) is 0.5394 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.5394(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure level and fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor B, C and D:

The P- value for the interaction effect BCD (exposure type, exposure level and fabric direction) is 0.7500 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.7500(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of exposure type, exposure level and fabric direction on the extent of color change at 1% level of significance.

Interaction effect of factor A, B, C and D:

The P- value for the interaction effect ABCD (fabric, exposure type, exposure level and fabric direction) is 0.8388 and the level of significance is 0.01.

Here, the P- value is greater than the level of significance.

That is, 0.8388(=P-value)>0.01(=α).

Thus, the null hypothesis is not rejected.

Hence, there is no sufficient of evidence to conclude that there is an interaction effect of fabric, exposure type, exposure level and fabric direction on the extent of color change at 1% level of significance.

Therefore, there is significant difference in the extent of color change with respect to the main effect A, B, D and interaction effects AB, AC are significant at 1% level of significance. The remaining second order interactions and third order interaction are not significant at 1% level of significance.

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Chapter 11 Solutions

Probability and Statistics for Engineering and the Sciences

Ch. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - The power curves of Figures 10.5 and 10.6 can be...Ch. 11.2 - In an experiment to assess the effects of curing...Ch. 11.2 - Prob. 17ECh. 11.2 - The accompanying data resulted from an experiment...Ch. 11.2 - A two-way ANOVA was carried out to assess the...Ch. 11.2 - The article Fatigue Limits of Enamel Bonds with...Ch. 11.2 - In an experiment to investigate the effect of...Ch. 11.2 - Prob. 22ECh. 11.2 - Prob. 23ECh. 11.2 - Prob. 24ECh. 11.2 - Prob. 25ECh. 11.2 - Prob. 26ECh. 11.3 - The output of a continuous extruding machine that...Ch. 11.3 - Prob. 28ECh. 11.3 - Prob. 29ECh. 11.3 - Prob. 30ECh. 11.3 - Nickel titanium (NiTi) shape memory alloy (SMA)...Ch. 11.3 - Prob. 32ECh. 11.3 - Prob. 33ECh. 11.3 - The article The Responsiveness of Food Sales to...Ch. 11.3 - Prob. 35ECh. 11.3 - Prob. 36ECh. 11.3 - Prob. 37ECh. 11.4 - The accompanying data resulted from an experiment...Ch. 11.4 - The accompanying data resulted from a 23...Ch. 11.4 - In a study of processes used to remove impurities...Ch. 11.4 - Prob. 41ECh. 11.4 - Prob. 42ECh. 11.4 - Prob. 43ECh. 11.4 - a. In a 24 experiment, suppose two blocks are to...Ch. 11.4 - a. An experiment was carried out to investigate...Ch. 11.4 - Prob. 46ECh. 11.4 - a. In a seven-factor experiment (A,, G), suppose a...Ch. 11.4 - The article Applying Design of Experiments to...Ch. 11 - The results of a study on the effectiveness of...Ch. 11 - Prob. 51SECh. 11 - Prob. 52SECh. 11 - In an automated chemical coating process, the...Ch. 11 - Coal-fired power plants used in the electrical...Ch. 11 - Impurities in the form of iron oxides lower the...Ch. 11 - Factorial designs have been used in forestry to...Ch. 11 - Prob. 57SECh. 11 - Prob. 58SECh. 11 - The bond strength when mounting an integrated...Ch. 11 - Prob. 60SECh. 11 - Prob. 61SE
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