   Chapter 11.4, Problem 28E

Chapter
Section
Textbook Problem

# AreaIn Exercises 25 and 26, find the area of the triangle with the given vertices. (Hint: 1 2 ‖ u × v ‖ is the area of the triangle having u and v as adjacent sides.) A ( 2 , − 3 , 4 ) , B ( 0 , 1 , 2 ) , C ( − 1 , 2 , 0 )

To determine

To calculate: The value of the area of a triangle whose vertices are given as, A(2,3,4), B(0,1,2) and C(1,2,0).

Explanation

Given:

The vertices of the triangle,

A(2,3,4), B(0,1,2) and C(1,2,0).

Formula used:

Area of the triangle is given by,

A=12u×v

Magnitude of ai+bj+ck is calculated as ai+bj+ck=a2+b2+c2.

Calculation:

Consider the vertices of the triangle,

A(2,3,4), B(0,1,2) and C(1,2,0).

Area of the triangle having u and v as adjacent sides is given by the below formula:

A=12u×v

Now,

AB=2i+4j2k=<2,4,2>

And,

AC=3i+5j+4k=<3,5,4>

And,

AB×AC=|

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Find f'(x) and f"(x). f(x)=x21+ex

Single Variable Calculus: Early Transcendentals, Volume I

#### In Exercises 107-120, factor each expression completely. 110. 12x2 3y2

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### Insert the proper sign (,=,or) to replace each . (a) 3.14 (b) 1000.1 (c) 312

Mathematical Applications for the Management, Life, and Social Sciences

#### Prove the identity. 45. sin cot = cos

Single Variable Calculus: Early Transcendentals 