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Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

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Section
BuyFindarrow_forward

Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

On a baseball diamond (a square), the bases are 90  ft apart. Use the Law of Sines to find the distance from home plate to second base.

Exercises 38 39

To determine

To find:

The distance from home place to second base of a baseball diamond

Explanation

Formula:

The Law of Sines,

sinαa=sinβb=sinγc

Where α, β, and γ is the acute angle of the triangle, and a, b, and c is the sides of the triangle.

Calculation:

Given,

The baseball diamond (square)

Let R be the home place S is the second base of the baseball diamond (square).

Here, length of bases are 90 ft.

Draw a line with the two points R and S

Then, RS¯ spilt the square as a two isosceles triangles whose length x.

By the isosceles triangle RFS,

F=90.

For any triangle

F+R+S=180

90+R+S=180

Since, R=S

90+R+R=180

90+2R=180

Add (90) on both sides,

90+2R90=18090

2R=90

Divide by 2 on both sides,

2R

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