   Chapter 11.5, Problem 35E

Chapter
Section
Textbook Problem

# Finding an Equation of a PlaneIn Exercises 39–44, find an equation of the plane that passes through the given point and is perpendicular to the given vector or line.PointPerpendicular to ( 1 , 3 , − 7 ) n = j

To determine

To calculate: The equation of the plane passing through the point (1,3,7) and perpendicular to the vector n=j.

Explanation

Given:

The plane passes through the point (1,3,7) and perpendicular to the vector n=j.

Formula used:

The equation of a plane in standard form is:

a(xx1)+b(yy1)+c(zz1)=0

Calculation:

To determine equation of a plane:

The point through which it is passing

And the normal vector to the plane should be known.

Now since, the provided point is (1,3,7) and normal vector is n=j.

Also now, use x1=1,y1=3 and z1=7

Point is (1,3,7)

Direction numbers a=0,b=1 and c=0

Normal vector is n=j in the standard equation of the plane

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