BuyFindarrow_forward

General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
ISBN: 9781305580343

Solutions

Chapter
Section
BuyFindarrow_forward

General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
ISBN: 9781305580343
Textbook Problem

A compound of carbon, hydrogen, and oxygen was burned in oxygen, and 1.000 g of the compound produced 1.434 g CO2 and 0.783 g H2O. In another experiment, 0.1107 g of the compound was dissolved in 25.0 g of water. This solution had a freezing point of −0.0894°C. What is the molecular formula of the compound?

Interpretation Introduction

Interpretation:

Given that 1.000 g of a compound containing Carbon, Hydrogen, Oxygen produced 1.434 g CO2 and 0.783 g H2O when burnt in oxygen. Freezing point of the solution of this compound is given.  Molecular formula of the compound has to be deduced.

Concept Introduction:

Depression in freezing point is a colligative property which refers to decrease in freezing point of the solution due to the addition of non-volatile solute. It is expressed as,

ΔTf = Kf.cm

Where,

ΔTf = depression in freezing pointKf = freezing point depression constantcm = molal concentration

Molality or molal concentration is one of the many parameters that is used to express concentration of a solution.  It is expressed as,

Molality = number of moles of solutemass of solvent in kg

Explanation

Given that mass of compound is 0.1107 g is dissolved in solvent water 25.0 g which is equivalent to 0.025 kg .

From the data given in the table 12.3 in text book, for water, Kf= 1.858°C/m

Freezing point of pure water is 0°C

Therefore, molality of the compound solution is,

ΔTf = Kf.cm

Rewriting the above equation,

cm  ΔTfKf Tf(solvent)-Tf(solution)20.0°C/m [0°C(-0.0894°C)]1.858°C/m = 0.04811 m

Moles of the compound are,

no. of moles = molality × mass of solvent = 0.04811 mol/kg × 0.025 kg 0.001203 mol

Molar mass of the compound is calculated as,

molar mass massno.of moles = 0.1107 g0.001203 mol = 92.02 g/mol

Given that 1.000 g of a compound containing Carbon, Hydrogen, Oxygen produced 1.434 CO2 and 0.783 H2O when burnt in oxygen. Calculate the empirical formula of compound using mass of C, O and H in 1.000 g of the compound

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 12 Solutions

Show all chapter solutions add
Sect-12.4 P-12.7ESect-12.4 P-12.8ESect-12.4 P-12.9ESect-12.4 P-12.10ESect-12.4 P-12.11ESect-12.5 P-12.12ESect-12.5 P-12.5CCSect-12.6 P-12.13ESect-12.6 P-12.14ESect-12.6 P-12.15ESect-12.7 P-12.16ESect-12.7 P-12.6CCSect-12.8 P-12.17ESect-12.8 P-12.7CCSect-12.9 P-12.18ESect-12.9 P-12.8CCCh-12 P-12.1QPCh-12 P-12.2QPCh-12 P-12.3QPCh-12 P-12.4QPCh-12 P-12.5QPCh-12 P-12.6QPCh-12 P-12.7QPCh-12 P-12.8QPCh-12 P-12.9QPCh-12 P-12.10QPCh-12 P-12.11QPCh-12 P-12.12QPCh-12 P-12.13QPCh-12 P-12.14QPCh-12 P-12.15QPCh-12 P-12.16QPCh-12 P-12.17QPCh-12 P-12.18QPCh-12 P-12.19QPCh-12 P-12.20QPCh-12 P-12.21QPCh-12 P-12.22QPCh-12 P-12.23QPCh-12 P-12.24QPCh-12 P-12.25QPCh-12 P-12.26QPCh-12 P-12.27QPCh-12 P-12.28QPCh-12 P-12.29QPCh-12 P-12.30QPCh-12 P-12.31QPCh-12 P-12.32QPCh-12 P-12.33QPCh-12 P-12.34QPCh-12 P-12.35QPCh-12 P-12.36QPCh-12 P-12.37QPCh-12 P-12.38QPCh-12 P-12.39QPCh-12 P-12.40QPCh-12 P-12.41QPCh-12 P-12.42QPCh-12 P-12.43QPCh-12 P-12.44QPCh-12 P-12.45QPCh-12 P-12.46QPCh-12 P-12.47QPCh-12 P-12.48QPCh-12 P-12.49QPCh-12 P-12.50QPCh-12 P-12.51QPCh-12 P-12.52QPCh-12 P-12.53QPCh-12 P-12.54QPCh-12 P-12.55QPCh-12 P-12.56QPCh-12 P-12.57QPCh-12 P-12.58QPCh-12 P-12.59QPCh-12 P-12.60QPCh-12 P-12.61QPCh-12 P-12.62QPCh-12 P-12.63QPCh-12 P-12.64QPCh-12 P-12.65QPCh-12 P-12.66QPCh-12 P-12.67QPCh-12 P-12.68QPCh-12 P-12.69QPCh-12 P-12.70QPCh-12 P-12.71QPCh-12 P-12.72QPCh-12 P-12.73QPCh-12 P-12.74QPCh-12 P-12.75QPCh-12 P-12.76QPCh-12 P-12.77QPCh-12 P-12.78QPCh-12 P-12.79QPCh-12 P-12.80QPCh-12 P-12.81QPCh-12 P-12.82QPCh-12 P-12.83QPCh-12 P-12.84QPCh-12 P-12.85QPCh-12 P-12.86QPCh-12 P-12.87QPCh-12 P-12.88QPCh-12 P-12.89QPCh-12 P-12.90QPCh-12 P-12.91QPCh-12 P-12.92QPCh-12 P-12.93QPCh-12 P-12.94QPCh-12 P-12.95QPCh-12 P-12.96QPCh-12 P-12.97QPCh-12 P-12.98QPCh-12 P-12.99QPCh-12 P-12.100QPCh-12 P-12.101QPCh-12 P-12.102QPCh-12 P-12.103QPCh-12 P-12.104QPCh-12 P-12.105QPCh-12 P-12.106QPCh-12 P-12.107QPCh-12 P-12.108QPCh-12 P-12.109QPCh-12 P-12.110QPCh-12 P-12.111QPCh-12 P-12.112QPCh-12 P-12.113QPCh-12 P-12.114QPCh-12 P-12.115QPCh-12 P-12.116QPCh-12 P-12.117QPCh-12 P-12.118QPCh-12 P-12.119QPCh-12 P-12.120QPCh-12 P-12.121QPCh-12 P-12.122QPCh-12 P-12.123QPCh-12 P-12.124QPCh-12 P-12.125QPCh-12 P-12.126QPCh-12 P-12.127QPCh-12 P-12.128QPCh-12 P-12.129QPCh-12 P-12.130QPCh-12 P-12.131QPCh-12 P-12.132QPCh-12 P-12.133QPCh-12 P-12.134QPCh-12 P-12.135QPCh-12 P-12.136QPCh-12 P-12.137QPCh-12 P-12.138QPCh-12 P-12.139QPCh-12 P-12.140QPCh-12 P-12.141QPCh-12 P-12.142QP

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

When added sugar is consumed in excess of calorie need, it alters blood lipids in potentially harmful ways. it ...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

A tuning fork with a frequency of f = 512 Hz is placed near the top of the tube shown in Figure P18.44. The wat...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Which body nominally governs the Law of the Sea?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin