Chapter 12, Problem 12.19P

Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Chapter
Section

Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

The shear strength of a normally consolidated clay can be given by the equation τ f = σ ′ tan 21°. The results of a consolidated-undrained test on the clay areChamber confining pressure = 225 kN/m2Deviator stress at failure = 112 kN/m2Determine:a. The consolidated-undrained (total stress) friction angleb. Pore water pressure developed in the specimen at failure

(a)

To determine

Find the consolidated undrained friction angle.

Explanation

Given information:

The chamber confining pressure (σ3) is 225kN/m2.

The angle of friction (ϕ) is 21°.

The deviator stress (Δσd)f at failure is 112kN/m2.

The equation of shear strength is τf=σtan21°.

Calculation:

Calculate the total pressure (σ1) using the equation:

σ1=σ3+(Δσd)f (1)

Substitute 225kN/m2 for σ3 and 112kN/m2 for (Δσd)f in Equation (1)

(b)

To determine

Find the pore water pressure developed in the specimen at failure.

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