Chapter 12, Problem 12.20P

### Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Chapter
Section

### Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

# If a consolidated-drained test is conducted on the clay specimen of Problem 12.19 with the same chamber-confining pressure of 225 kN/m2, what would be the deviator stress at failure?12.19 The shear strength of a normally consolidated clay can be given by the equation τ f = σ ′ tan 21°. The results of a consolidated-undrained test on the clay areChamber confining pressure = 225 kN/m2Deviator stress at failure = 112 kN/m2Determine:a. The consolidated-undrained (total stress) friction angleb. Pore water pressure developed in the specimen at failure

To determine

Find the deviator stress at failure.

Explanation

Given information:

The chamber confining pressure (σ3) is 225kN/m2.

The angle of friction ϕ is 21°.

The deviator stress (Δσd)f at failure is 112kN/m2.

Calculation:

Calculate the major principal stress (σ1) on the clay specimen using the formula.

σ1=σ3tan2(45+ϕ2) (1)

Here, σ1 is the major effective principal stress, σ3 is the minor effective principal stress, and ϕ is angle of friction.

Substitute 225kN/m2 for (σ3) and 21° for ϕ in Equation (1).

σ1=225tan2(45+212)=225tan2(55

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started