Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 12, Problem 12.23P
(a)
To determine
Find the undrained cohesion at a depth of
(b)
To determine
Find the design value of undrained shear strength by using Bjerrum’s correction factor.
(c)
To determine
Find the new undrained cohesion.
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In a drained triaxial compression test, a saturated specimen of cohesionless sand fails at a deviator stress of 450 kN/m2 when the cell pressure was 135 kN/m2. Find the effective angle of shearing resistance of sand.
a. 64 deg 15 min b. 26 deg 30 min c. 38 deg 30 min d. 48 deg 15 min
The soil stress state is shown in the figure, σx = 10 kN/m2, σy = 50 kN/m2, τxy = -10 kN/m2:(1) Please use Mohr circle to draw the soil stress state(2) Calculate the maximum principal stress σ1 and the minimum principal stress σ3(3) Please find the (pole) position(4) What is the angle of intersection between the maximum principal stress surface and the horizontal plane?
In a drained triaxial compression test, a saturated specimen of cohesionless sand fails at a deviator stress of 450 kN/m2 when the cell pressure was 135 kN/m2. Find the effective angle of shearing resistance of sand.
a.26 deg 30 min
b.48 deg 15 min
c.64 deg 15 min
d.38 deg 30 min
With Free Body Diagram
Chapter 12 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- Refer to the soil profile shown. Given H1 = 9.76m and H2 = 4.22 m. If the ground water table rises by 2.41 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.56, e =0.61. Properties of clay: Gs = 2.79, e = 0.83.arrow_forwardThe soil stress state is shown in the figure, σx = 10 kN/m2, σy = 50 kN/m2, τxy = -10 kN/m2 What is the angle of intersection between the maximum principal stress surface and the horizontal plane?arrow_forwardQuestion-2: A soil profile is shown in Figure 2.1. Calculate and plot the variation of total vertical stress, pore pressure and effective vertical stress with depth.arrow_forward
- In a drained triaxial compression test, a saturated specimen of cohesionless sand fails at a deviator stress of 450 kN/m2 when the cell pressure was 135 kN/m2. Find the effective angle of shearing resistance of sand. show Free body Diagram. a.48 deg 15 min b.26 deg 30 min c.38 deg 30 min d.64 deg 15 minarrow_forwardA saturated specimen of cohesionless sand was tested under drained conditions in a triaxial compression test apparatus and the sample failed at a deviator stress of 482 kN/m2 and the plane of failure made an angle of 60° with the horizontal. Find the magnitude of the principal minor stress in kPa. include diagramarrow_forwardDetermine the internal friction angle of a cohesionless soil that has been tested under a normal stress of 200 kN/m2 and and fails at shear stress of 100 kN/m2.arrow_forward
- A sample of dry, cohesionless soil has an angle of internal friction of 30º. If the minor principal stress is 160 KPa, at what values of normal stress is the sample likely to fail?arrow_forwardA cylindrical sample of soil having a cohesion of 80 kN/m2 and an angle of internal friction of 20°is subjected to a cell pressure of 100 kN/m2. Determine the maximum deviator stress at which the sample will fail in kPa. Show diagramarrow_forwardA soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore waterpressureat points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given belowarrow_forward
- Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.59, e = 0.61. Properties of clay: Gs = 2.74, e = 0.86. Round off to two decimal places. Answer: 13.95arrow_forwardSolve it quick? Triaxial test (CU) is performed on a clay for a confining pressure of 110 kPa. If the deviator stress and pore-water pressure were 70 kpa and 55 kpa respectively then determine the internal friction angle.arrow_forwardIn a drained triaxial compression test, a saturated specimen of cohesionless sand fails at a deviator stress of 450 kN/m2 when the cell pressure was 135 kN/m2. Find the angle of inclination of the failure plane with the horizontal. Show diagramarrow_forward
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