   Chapter 12, Problem 12.57PAE ### Chemistry for Engineering Students

4th Edition
Lawrence S. Brown + 1 other
ISBN: 9781337398909 ### Chemistry for Engineering Students

4th Edition
Lawrence S. Brown + 1 other
ISBN: 9781337398909
Textbook Problem

# Solid Na2SO4 is added slowly to a solution that is 0.10 M in PbfNO,), and 0.10 M in Ba(NO})2. In what order will solid PbSO4 and BaS04 form? Calculate the percentage of B.r * that precipitates just before PbSO4 begins to precipitate.

Interpretation Introduction

To determine: Solid Na2SO4 is added slowly to a solution that 0.01M in Pb(NO3)2and 0.01M in Ba(NO3)2. In what order will solid PbSO4and BaSO4 form.

Determine the percentage of Ba2+ that precipitates just before PbSO4 begins to precipitate.

Explanation

First find the concentration SO42 for equilibrium of PbSO4and BaSO4 in the solution.

PbSO4(S)Pb2+(aq)+SO42(aq)

Concentration of Pb(NO3)2 in the solution is 0.10M. Due to this initial concentration Pb2+(aq)=0.10M.

Now let x M of NaSO4 is added before precipitation of PbSO4(S).

 PbSO4(S) Pb(aq) SO42− Initial concentration due to PbS O 4 ( S ) Solid 0.10 0 Change in concentration due to addition of N a 2 S O 4 Solid 0 x Final concentration 0.10 x

KSP=[Pb2+][SO42]KSP of PbSO4=1.8×107[Pb2+]=0.10M[SO42]=xM1.8×108=(0.10)×(x)x=1.8×108M

Minimum concentration of SO42 in solution to start precipitation of PbSO4=1.8×107M.

Similarly find out minimum concentration of SO42 to start precipitation of BaSO4.

BaSO4(S)Ba2+(aq)+SO42(aq)

Concentration of Ba(NO3)2 in the solution is 0.10M due to this there are initial concentration of Ba2+(aq) and it is equal to 0.10M

Now let x M of NaSO4 is added just before to start the precipitation of BaSO4(S).

 BaSO4(S) Ba(aq) SO4(aq) Initial concentration due to Ba ( N O 3 ) 2 Solid 0

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