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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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rite electron configurations for the most stable ion formed by each of the following elements. Do not use the noble gas notation. Write out the complete electron configuration.

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Element Electron Configuration of the most stable Ion

msp;  Na

msp;  K

msp;  Li

msp;  Cs

Interpretation Introduction

Interpretation:

The electron configurations for the most stable ion that is formed by the given atoms are to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

An ion that is formed by losing an electron from a neutral atom is known as cation. An ion that is formed by gaining an electron to a neutral atom is known as anion.

Explanation

The atomic number of sodium is 11. Thus, the electron configuration of the given element, sodium Na, is 1s22s22p63s1. If sodium loses one electron then it achieves the most stable electron configuration same as that of the noble gas, neon with Z=10. Thus, the electron configurations for the most stable, Na+ ion is,

1s22s22p6

The atomic number of potassium is 19. Thus, the electron configuration of the given element, potassium K, is 1s22s22p63s23p64s1. If potassium loses one electron then it achieves the most stable electron configuration same as that of the noble gas, argon with Z=18. Thus, the electron configurations for the most stable, K+ ion is,

1s22s22p63s23p6

The atomic number of lithium is 3. Thus, the electron configuration of the given element, lithium Li, is 1s22s1

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