Chapter 12, Problem 12.83FU

Interpretation Introduction

Interpretation:

The volume of chlorpromazine administered to the patient should be calculated.

Concept Introduction:

Mass/volume percent (m/V) concentration is defined as the mass of solute in grams for 100 mL of the solution. Here, mass of solute should be in grams and unit of volume of solution should be in millilitres.

Mathematically,

  $\begin{array}{l}\text{mass /volume percent}\left(m/V\right)=\frac{\text{mass of solute}\left(g\right)}{\text{volume of solute}\left(\text{mL}\right)+\text{volume of solvent}\left(\text{mL}\right)}\times 100\%\\ =\frac{\text{mass of solute}\left(g\right)}{\text{volume of solution}\left(\text{mL}\right)}\times 100\%\end{array}$

Answer to Problem 12.83FU

3 mL

Explanation of Solution

The stock solution is 2.5% mass by volume. This means 2.5 g of chlorpromazine is present in 100 mL of solution.

Thus, 1 g of chlorpromazine will be there in $\frac{100}{2.5}\text{ mL}$ of the solution.

Thus, the volume of solution containing given mass of chlorpromazine will be:

  $V=\frac{100\text{ mL}}{2.5\text{ g}}\times \text{0}\text{.075 g =3 mL}$

Conclusion

Thus, the volume of chlorpromazine administered to the patient will be 3 mL.