   # A sample of water contains 2.0 ppm NaF . How many grams of NaF are contained in 25 L of water? ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 12.8YT
Textbook Problem
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## A sample of water contains 2.0 ppm NaF . How many grams of NaF are contained in 25 L of water?

Interpretation Introduction

Interpretation:

The mass of NaF, in grams, present in 25 L of water is to be determined.

Concept Introduction:

Concentration of a solution can be calculated, in parts per million, with the help of masses of the solute and solution.

The density of the solution is defined as the mass of the solution per unit volume of the solution. The expression for density is as follows;

d=mV

Here, m is the mass of the solution, V is the volume of the solution, and d is the density of the solution.

Concentration of a solution in parts per million is expressed as follows:

ppm=grams solutegrams solution×106

### Explanation of Solution

To convert liters (L) to mL, first write the correct conversion factor by using the following relationship:

1 L=1000 mL

Thus, the correct conversion factor will be (1000 mL1 L).

Multiply the conversion factor with the given quantity and cancel units to get the desired quantity. Hence,

25 L×1000 mLL=25×103 mL

Density of water is 1.0 g/mL. The relation between density and mass is as follows:

d=mV

Rearrange the above expression for the mass of the solution as follows:

m=(d)(V)

Substitute, 25×103 mL for V and 1.0 g/mL for d in the above expression as follows:

m=(1.0gmL)(25×103 mL)=25×103 g

The ppm is generally reported in terms of grams

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