Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 12, Problem 12.9E
Interpretation Introduction

Interpretation:

The structural formulas and the IUPAC names for the 13 alkene isomers of C6H12 are to be drawn.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are:

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution & Answer
Check Mark

Answer to Problem 12.9E

The structural formulas and the IUPAC names of the 13 alkene isomers of C6H12 are given below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  1

Explanation of Solution

The first alkene isomer of C6H12 is hex-1-ene. It consists of six carbon atoms in a straight chain and double bond between the first and the second carbon atoms. The structure of hex-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  2

Figure 1

The second alkene isomer of C6H12 is hex-2-ene. It consists of six carbon atoms in a straight chain and double bond between the second and the third carbon atoms. The structure of hex-2-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  3

Figure 2

The third alkene isomer of C6H12 is hex-3-ene. It consists of six carbon atoms in a straight chain and double bond between the third and the fourth carbon atoms. The structure of hex-3-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  4

Figure 3

The fourth alkene isomer of C6H12 is 2-methylpent-1-ene. It consists of five carbon atoms in a straight chain and double bond between the first and the second carbon atoms. A methyl group is present as a substituent on the second carbon atom. The structure 2-methylpent-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  5

Figure 4

The fifth alkene isomer of C6H12 is 3-methylpent-1-ene. It consists of five carbon atoms in a straight chain and double bond between the first and the second carbon atoms. A methyl group is present as a substituent on the third carbon atom. The structure 3-methylpent-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  6

Figure 5

The sixth alkene isomer of C6H12 is 4-methylpent-1-ene. It consists of five carbon atoms in a straight chain and double bond between the first and the second carbon atoms. A methyl group is present as a substituent on the fourth carbon atom. The structure 4-methylpent-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  7

Figure 6

The seventh alkene isomer of C6H12 is 2-methylpent-2-ene. It consists of five carbon atoms in a straight chain and double bond between the second and the third carbon atoms. A methyl group is present as a substituent on the second carbon atom. The structure 2-methylpent-2-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  8

Figure 7

The eighth alkene isomer of C6H12 is 3-methylpent-2-ene. It consists of five carbon atoms in a straight chain and double bond between the second and the third carbon atoms. A methyl group is present as a substituent on the third carbon atom. The structure 3-methylpent-2-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  9

Figure 8

The ninth alkene isomer of C6H12 is 4-methylpent-2-ene. It consists of five carbon atoms in a straight chain and double bond between the second and the third carbon atoms. A methyl group is present as a substituent on the fourth carbon atom. The structure 4-methylpent-2-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  10

Figure 9

The tenth alkene isomer of C6H12 is 2-ethylbut-1-ene. It consists of four carbon atoms in a straight chain and double bond between the first and the second carbon atoms. An ethyl group is present as a substituent on the second carbon atom. The structure 2-ethylbut-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  11

Figure 10

The eleventh alkene isomer of C6H12 is 2, 3-dimethylbut-2-ene. It consists of four carbon atoms in a straight chain and double bond between the second and the third carbon atoms. One methyl group each is present as a substituent on the second and the third carbon atoms. The structure 2, 3-dimethylbut-2-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  12

Figure 11

The twelfth alkene isomer of C6H12 is 2, 3-dimethylbut-1-ene. It consists of four carbon atoms in a straight chain and double bond between the first and the second carbon atoms. One methyl group each is present as a substituent on the second and the third carbon atoms. The structure 2, 3-dimethylbut-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  13

Figure 12

The thirteenth alkene isomer of C6H12 is 3, 3-dimethylbut-1-ene. It consists of four carbon atoms in a straight chain and double bond between the first and the second carbon atoms. Two methyl groups are present as a substituent on the third carbon atom. The structure 3, 3-dimethylbut-1-ene is shown below.

Chemistry for Today: General, Organic, and Biochemistry, Chapter 12, Problem 12.9E , additional homework tip  14

Figure 13

Conclusion

The structural formulas and the IUPAC names of the 13 alkene isomers of C6H12 have been rightfully stated.

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Describe geometric isomerism. With the aid of diagrams use the molecular formula C5H10 to explain geometric isomerism in alkenes.

Chapter 12 Solutions

Chemistry for Today: General, Organic, and Biochemistry

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