   Chapter 12, Problem 17P

Chapter
Section
Textbook Problem

A gas is compressed at a constant pressure of 0.800 atm from 9.00 L to 2.00 L. In the process, 400. J of energy leaves the gas by heat. (a) What is the work done on the gas? (b) What is the change in its internal energy?

(a)

To determine
The work done on the gas in compression.

Explanation

Given Info:

The pressure of the gas is 0.8atm .

Initial volume of thy gas is 10L .

Finial volume of the gas is 2L .

Formula to calculate the work done on the gas is,

W=P(VfVi)

• P is the pressure of the gas
• Vf is the finial volume of gas after the compression
• Vi is the initial of gas before compression

Substitute 0.8atm for P, 10L for Vi , 2L for Vf to find the work done on the gas,

W=(0

(b)

To determine
the change in internal energy of the gas in compression.

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